![]() |
|
|
#34 |
|
Sep 2016
33410 Posts |
I'm mildly amused by this...
There are only a handful of known Mersenne Primes after many years of searching. Did you really think finding another one is as easy as letting a computer sit for 7 days?
Last fiddled with by Mysticial on 2016-11-06 at 02:59 |
|
|
|
|
|
#35 |
|
Sep 2002
Database er0rr
1110101100102 Posts |
|
|
|
|
|
|
#36 |
|
Nov 2016
43 Posts |
i want only one i can get and a new start not a thing have happen a beautiful number
|
|
|
|
|
|
#37 |
|
Nov 2016
43 Posts |
you tell me i have to talk with and administrator is true or not ??
|
|
|
|
|
|
#38 |
|
Nov 2016
538 Posts |
not cool with me i was on it and reaching 99.99 i was sure but ok i try i was closed very closed
|
|
|
|
|
|
#39 |
|
Sep 2002
Database er0rr
1110101100102 Posts |
You have a choice:
1. let things happen automatically: Marry you account details. 2. Do things manually: use http://www.mersenne.org/manual_result/ |
|
|
|
|
|
#40 |
|
Nov 2016
43 Posts |
if he reach 99.99 is not product by 2 primes?
|
|
|
|
|
|
#41 |
|
Sep 2002
Database er0rr
2·32·11·19 Posts |
|
|
|
|
|
|
#42 |
|
Nov 2016
1010112 Posts |
what is the true ? what is marry account ? and why result manually i have sen 10 time?
|
|
|
|
|
|
#43 |
|
Nov 2016
43 Posts |
whats happens please tell me i don't understand its late here
|
|
|
|
|
|
#44 |
|
Sep 2002
Database er0rr
2·32·11·19 Posts |
The LL (Lucas-Lehmer) test works like this. Start with 4. The square and subtract 2: 4^2-2 = 14. Next take the result, 14, square it and subtract 2: 14^2-2 = 194. Repeat this s <- s^2-2 millions of times. When the number gets too big we can reduce it by the candidate number, so that the numbers we are dealing with are manageable.
Here is an example. M7 = 127. We do 5 iterations of LL: 14 194 37634 1416317954 2005956546822746114 As you can see the numbers get very big quickly. So in practice we look only at the remainders when divided by 127. In fact, we always look at only the remainders, noting for example 67^2-2 mod 127 is 42: 14 67 42 111 0 Bingo! The result of the 5th iteration is 0. It says nothing about the number of factors, apart from it 1 when prime and greater than 1 when it is not prime. Last fiddled with by paulunderwood on 2016-11-06 at 03:22 |
|
|
|