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#78 |
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1976 Toyota Corona years forever!
"Wayne"
Nov 2006
Saskatchewan, Canada
22×7×167 Posts |
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#79 | |
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Romulan Interpreter
Jun 2011
Thailand
7·1,373 Posts |
Quote:
![]() Wrong thread. See my post #59 |
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#80 | ||
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Basketry That Evening!
"Bunslow the Bold"
Jun 2011
40<A<43 -89<O<-88
3×29×83 Posts |
Quote:
Quote:
), what was the sigma?
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#81 |
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"Curtis"
Feb 2005
Riverside, CA
113758 Posts |
Here I was excited that this thread had gained some interesting content.. gossiping about factors that others found seems within the scope of this otherwise useless location.
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#82 |
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Feb 2013
1CA16 Posts |
Have a look here, please.
http://factordb.com/index.php?id=1100000000805654118 http://factordb.com/index.php?id=1100000000805654221 The C139 in the second link. Here it apparently meets at an almost 90 degree angle. The two factors were found separately, so no need giving this one a try. I will update this one a little later. Last fiddled with by storflyt32 on 2015-11-10 at 21:26 |
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#83 |
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Feb 2013
2×229 Posts |
http://factordb.com/index.php?id=1100000000805963658
Really, I did have the P23 and P27 here and was working on the remaining two. Apparently it became work done this time as well. |
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#84 |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
36·13 Posts |
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#85 |
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Feb 2013
2·229 Posts |
Congratulations with your lucky hit.
I am able to find this. http://factordb.com/index.php?id=1100000000812506211 If I choose to "divide this number (the C107) from RSA-1024, I apparently end up with a C203, which again has been factorized into a C186. So if I choose the More information icon, I next am able to see that there could be added a P11 (P11 = 10275403429), as a product or factor, making up a number which is slightly larger. http://factordb.com/index.php?id=1100000000812506210 If I next "divide" RSA-1024 with this number and next start factorizing, you are able to get a little farther, but only with getting rather some smaller factors this time. http://factordb.com/index.php?id=1100000000812694618 Next "dividing" RSA-1024 with the FF117 (which could be assumed to be a C117) as well when being used in such a "dividing" fashion. http://factordb.com/index.php?id=1100000000812694637 This leaves me with the following question here. Which number of the C186 or the C163 is the most difficult one to factorize? My guess is that the C186 is the more difficult number to factorize in this case. Became a little too much to handle here. Really when saying I or me, it could in fact be you as well, or maybe vice versa. Hope the meaning of it became clear. Edit: Possibly getting it wrong here. The C186 is having a P31 factor. Last fiddled with by storflyt32 on 2016-01-04 at 19:15 |
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#86 |
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Romulan Interpreter
Jun 2011
Thailand
7×1,373 Posts |
oh no, he is back! happy new year...
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#87 |
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Feb 2013
2·229 Posts |
Thank you very much!
http://factordb.com/index.php?id=1100000000812713232 I was able to fully factorize this number a short while ago. The P18 is an easy one to factor. The remaining number was previously a C182, but this number became factored in only some 2917 seconds. http://factordb.com/index.php?id=1100000000812713241 Here is the mirror, or opposite number of this factor around RSA-1024. Take the three largest factors in the first link and add (or multiply) the P18 in order to get the second link. The C106 in the second link most likely is a quite difficult one to factorize. Last fiddled with by storflyt32 on 2016-01-05 at 09:44 |
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#88 |
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Feb 2013
1CA16 Posts |
Anyway, just for your information, I am able to see that RSA-2048 "divided" with 2^1279-1 has not been fully factored.
http://factordb.com/index.php?id=1100000000812734033 Giving the C197 a try right now. Last fiddled with by storflyt32 on 2016-01-05 at 14:27 |
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