Pseudo-mathematical gibberings (volume 9a)

[retina]

Originally Posted by retina

Okay, let's start with MMMMM2 and then move on to RSA4096. Just one factor from each will be enough. Although I am not sure about the ordering in terms of hardness so doing them in the opposite order will be fine also.

So, are we there yet? It's been two minutes.

[Batalov]

Ah yes, but what part of "when it costs you nothing" was unclear? ;-)

I am in a generous mood, and I step up from "nothing" to 2 cents. Here they are -

[retina]

Originally Posted by Batalov

Ah yes, but what part of "when it costs you nothing" was unclear? ;-)

I am in a generous mood, and I step up from "nothing" to 2 cents. Here they are -

Okay, so you are saying it will cost me 2 cents. Then it is a deal. Factors first, then I'll pay.

[Batalov]

No, you will get something for nothing if it costs me nothing. It could be much more valuable to you, though. That's what the H.C.Anderson's field mouse told me when I was a little child and I pondered for a while and decided, "you are right, little furry dude, this makes sense".

But because I am still in a generous mood, of course I will help you factor those little trifles!

MMMMM2 (rather properly written MMMMMII, because as you know you are mixing Roman and arabic digits, but that's an easy mistake to make) = 2 · 41 · 61.
RSA4096 is even easier and is equal to 2 · 2 · 2 · 2 · 2 · 2 · 2 · 2 · 2 · 2 · 2 · 2 South African rands.

[retina]

Originally Posted by Batalov

But because I am still in a generous mood, of course I will help you factor those little trifles!

MMMMM2 (rather properly written MMMMMII, because as you know you are mixing Roman and arabic digits, but that's an easy mistake to make) = 2 · 41 · 61.
RSA4096 is even easier and is equal to 2 · 2 · 2 · 2 · 2 · 2 · 2 · 2 · 2 · 2 · 2 · 2 South African rands.

Well that is absolutely precisely exactly¹ what I wanted. So as promised here is my payment.



¹Not!

[storflyt32]

C75 = 480803331333445101741328545933891153031908054791180635359833574231002718203

Same problem here as well.

Edit: Found a PRP614 just two minutes ago. Will be reporting it shortly.

BTW: What is the "official" RSA-4096 number?

Thanks for any answer!

[xilman]

Originally Posted by storflyt32

C75 = 480803331333445101741328545933891153031908054791180635359833574231002718203
Thanks for any answer!

Just because we can doesn't mean we will.

[Batalov]

Originally Posted by storflyt32

C75 = 480803331333445101741328545933891153031908054791180635359833574231002718203

Same problem here as well.

Edit: Found a PRP614 just two minutes ago. Will be reporting it shortly.

BTW: What is the "official" RSA-4096 number?

Thanks for any answer!

Like Paul said, only the first request is usually free, or else there will be no end to it. You need fifteen merits for a solution of this problem.

Like someone else said, Give a man a fish, and you have fed him for today.Teach a man to fish, and he will sit in the boat and drink beer all day.

[xilman]

Originally Posted by Batalov

Like Paul said, only the first request is usually free, or else there will be no end to it. You need fifteen merits for a solution of this problem.

Like someone else said, Give a man a fish, and you have fed him for today.Teach a man to fish, and he will sit in the boat and drink beer all day.

I prefer: light a man a fire and you warm him for a day. Set a man on fire and you warm him for the rest of his life.

[storflyt32]

C80 = 47696710294705499280359610260517275637267727477058055991019082347840906420354827

This C80 is a stubborn one and right now I do not have the factors for it.

You are welcome to give it a try.

Thanks!

[Jayder]

How are you trying to factor these numbers? Pocket calculator?