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Old 2014-08-23, 00:02   #78
alpertron
 
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Quote:
Originally Posted by R.D. Silverman View Post
No. You incorrectly assume that the probabilities are the same
as if no prior factor had been found.

Apply Erdos-Kac. Look at the expected number of new factors given
12 found already. Now look at the ORDER STATISTICS for the
remaining factors.

If p is a factor of a much larger integer n, then the expected value for the
next largest factor is p^e. This can be derived by applying Erdos-Kac
and then looking at the ORDER STATISTICS.
According to the known data from http://www.mersenne.ca/manyfactors.php ,

Code:
10 prime factors known for 2 Mersenne numbers
9 prime factors known for 9 Mersenne numbers
8 prime factors known for 86 Mersenne numbers
7 prime factors known for 346 Mersenne numbers
6 prime factors known for 1,788 Mersenne numbers
5 prime factors known for 16,262 Mersenne numbers
4 prime factors known for 139,199 Mersenne numbers
These statistics appear to imply that the probability of finding a new prime factor is relatively independent of known number of prime factors.

Last fiddled with by alpertron on 2014-08-23 at 00:19 Reason: prime factors, not factors
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Old 2014-08-23, 00:08   #79
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Careful... Just because we haven't found many doesn't mean that there aren't. For most of these, we've stopped looking because with the exception of a bit of hobbying, nobody cares. A select few might want a factor for EVERY candidate, regardless of LL result.
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Old 2014-08-23, 00:16   #80
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OK. Let me rephrase my thinking differently. Suppose that we know not 10 but 9 prime factors of M7508981. The probability of finding the tenth prime factor would be so extremely tiny according to Bob that it would be nearly impossible that we found the 10th prime factor.

Then we can continue backtracking, and finally we should conclude that it would be impossible with the current bounds to find more, than say 5 prime factors. This is not what occurs according to my previous post.

So it appears that something in Bob's argument is not entirely correct.
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Old 2014-08-23, 00:19   #81
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@Silverman

No reason to be rude, your comments are being less than helpful. I will be ignoring your inquiries until you choose to be civil.
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Old 2014-08-23, 01:05   #82
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Quote:
Originally Posted by pdazzl View Post
The likelihood of ECM'ing a 45 digit factor. I do not know the probability of this.
Given that the factor bound is 25 digits, I'd estimate the probability at little less than 50%, but the problem is that you will need a lot of people running ECM in a lot of computers each in order to complete the 45-digit level. Notice that adding 5 digits is about 10 times slower, so adding 20 digits is about ... slower (fill in the blanks).
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Old 2014-08-23, 04:03   #83
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Quote:
Originally Posted by R.D. Silverman View Post
If p is a factor of a much larger integer n, then the expected value for the next largest factor is p^e.
I was going to ask why this is larger than the heuristic in post 59, which is p^2, but then I realized that you have the mean and post 59 has the median. The method in post 59 also handles the case where trial factoring has cleared beyond a known prime - does your method say n^e for that case?.
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Old 2014-08-23, 06:50   #84
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Well, Silverman is suggesting a breadth-first search for factors. In other words, give each exponent the same amount of work until we can find a reason to focus a lot of work onto a specific one.

The counter-argument is that given that the remainder of M7508981 is not PRP and that there are already 10 known primes, it follows that there ARE 12 factors and we're looking for the eleventh (to do more PRP on the leftover, etc etc). This IS the reason to put so much work onto a specific exponent.

The reason certain exponents have two or three factors and that certain others have eight or nine or ten are because the distribution isn't fixed in stone, but made in a statistical way. The occasional exponent will give 10 small factors like our friend M7508981 which is just an outlier (hence why we're bothering to look at it at all).

While he is very direct with our massive stupidity he certainly is not with the mental exercise he wants us to perform. I believe what he is suggesting is that we ought to show that we won't be more successful finding another outlier with many (as in even more than 10) factors versus finding the actual eleventh and twelfth factors of this specific one.

I don't think he actually knows which path would be more successful. Instead he wants us to justify every little thing we're doing instead of just doing something for the hell of it.

Last fiddled with by TheMawn on 2014-08-23 at 06:51
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Old 2014-08-23, 08:00   #85
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Quote:
Originally Posted by TheMawn View Post
Well, Silverman is suggesting a breadth-first search for factors. In other words, give each exponent the same amount of work until we can find a reason to focus a lot of work onto a specific one.

The counter-argument is that given that the remainder of M7508981 is not PRP and that there are already 10 known primes, it follows that there ARE 12 factors and we're looking for the eleventh (to do more PRP on the leftover, etc etc). This IS the reason to put so much work onto a specific exponent.

The reason certain exponents have two or three factors and that certain others have eight or nine or ten are because the distribution isn't fixed in stone, but made in a statistical way. The occasional exponent will give 10 small factors like our friend M7508981 which is just an outlier (hence why we're bothering to look at it at all).
So, emotional justification rather than mathematical?

Not saying there's anything wrong with that, only trying to make it explicit. AIU Bob's earlier statements here and in other threads suggests he agrees (the nothing wrong bit) but he wants people to understand why they are doing what they are doing and not to mislead (inadvertently) others into thinking that an alternative justification is present.

Quote:
Originally Posted by TheMawn View Post
While he is very direct with our massive stupidity he certainly is not with the mental exercise he wants us to perform. I believe what he is suggesting is that we ought to show that we won't be more successful finding another outlier with many (as in even more than 10) factors versus finding the actual eleventh and twelfth factors of this specific one.

I don't think he actually knows which path would be more successful. Instead he wants us to justify every little thing we're doing instead of just doing something for the hell of it.
Quite right too, IMAO!

Paul

Last fiddled with by xilman on 2014-08-23 at 08:02 Reason: Must try not to (inadvertently) split infinitives.
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Old 2014-08-23, 08:34   #86
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Quote:
Originally Posted by pdazzl View Post
@Silverman

No reason to be rude, your comments are being less than helpful. I will be ignoring your inquiries until you choose to be civil.
There is/was every reason to be rude, because your comments showed
that rather than "will be ignoring until you choose to be civil",
you have been IGNORING THEM ALL ALONG.

Furthermore, I tell you something and then you, despite not knowing any math
ARGUE ABOUT IT.

Last fiddled with by R.D. Silverman on 2014-08-23 at 08:37
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Old 2014-08-23, 09:00   #87
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Quote:
Originally Posted by xilman View Post
So, emotional justification rather than mathematical?

Not saying there's anything wrong with that, only trying to make it explicit. AIU Bob's earlier statements here and in other threads suggests he agrees (the nothing wrong bit) but he wants people to understand why they are doing what they are doing and not to mislead (inadvertently) others into thinking that an alternative justification is present.

Quite right too, IMAO!

Paul
"I don't think he actually knows which path would be more successful. Instead he wants us to justify every little thing we're doing instead of just doing something for the hell of it."


This is correct. I do not know which would be more successful.
I strongly suspect (based on some experience with similar things) that
a breadth-first search will succeed with less expected work.
I have not crunched through the numbers,

Note that the work being performed here is a random variable.
Even if one has success with a depth-first search, it does not prove
that such a search will succeeed on average with less work.

I do not have the tools or the time (or the inclination) to crunch the
numbers to find out which method would be better. I can only
suggest the methodology to the problem.

DAMN IT! I'm trying to get people to apply some analysis before
blindly plunging into a computation. Otherwise it is just "try it
and hope".

I am, of course, assuming that the goal is to find an M_p with at least
13 prime factors in the most efficient manner possible so that this
group effort succeeds in as little elapsed time as possible..
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Old 2014-08-23, 13:48   #88
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Quote:
Originally Posted by alpertron View Post
According to the known data from http://www.mersenne.ca/manyfactors.php ,

Code:
10 prime factors known for 2 Mersenne numbers
9 prime factors known for 9 Mersenne numbers
8 prime factors known for 86 Mersenne numbers
7 prime factors known for 346 Mersenne numbers
6 prime factors known for 1,788 Mersenne numbers
5 prime factors known for 16,262 Mersenne numbers
4 prime factors known for 139,199 Mersenne numbers
The previous values are for all Mersenne numbers with exponents less than 232. I think it is better to filter to the range 1M to 10M (so we can perform the PRP test on the cofactor). In this way the statistics from http://www.mersenne.ca/manyfactors.p...n=4&fac_max=10 are:

Code:
10 prime factors known for 1 Mersenne number
9 prime factors known for 1 Mersenne number
8 prime factors known for 5 Mersenne numbers
7 prime factors known for 16 Mersenne numbers -> 0.003 % 
6 prime factors known for 114 Mersenne numbers -> 0.019 %
5 prime factors known for 682 Mersenne numbers -> 0.116 %
4 prime factors known for 4,337 Mersenne numbers -> 0.740 %

Last fiddled with by alpertron on 2014-08-23 at 13:56
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