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#56 |
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"Forget I exist"
Jul 2009
Dumbassville
26×131 Posts |
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#57 |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
2·47·101 Posts |
Your post makes about as much sense as this test from Being John Malkovich, or closer to this forum these scribbles. Well, not much can be done about "Kathy", but can you before posting first shape your thoughts in some coherent form? hmm?
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#58 | |
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"Forget I exist"
Jul 2009
Dumbassville
26×131 Posts |
Quote:
1) Is there anything special above what is special about the k values in factors of normal mersenne factors, hidden within the k values of double mersenne factors ? |
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#59 |
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Apr 2014
7·17 Posts |
This is somewhat but not directly related to the topic; something I've noticed(checking mersenne.ca) is that it appears no mersenne prime (or primes that show up as factors in the Lucas Lehmer chain) are factors for any mersenne candidates. Is there a reason/property anyone can see for why this might be?
14 --- Factors 2 7 194 --- Factors 2 97 194^2-2 --- Factors 2 31 607 (194^2-2)^2-2 --- Factors 2 708158977 ((194^2-2)^2-2)^2-2 --- Factors 2 127 7897466719774591 (((194^2-2)^2-2)^2-2)^2-2) --- Factors 2 22783 265471 592897 2543310079 220600496383 ((((194^2-2)^2-2)^2-2)^2-2)^2-2 --- Factors 2 113210499946729046527 71510428488234435849323250891975205208728978040847871 (((((194^2-2)^2-2)^2-2)^2-2)^2-2)^2-2 --- Factors 2 3867637345756894712411491994657791 4141173562324283362391211134773751434933274141271057666869711137355139870107549772907161419207982079 ((((((194^2-2)^2-2)^2-2)^2-2)^2-2)^2-2)^2-2 --- Factors 2 1049179854847 27293256153178849431531258375109421840383 |
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#60 | |
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"Forget I exist"
Jul 2009
Dumbassville
26×131 Posts |
Quote:
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#61 |
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"Forget I exist"
Jul 2009
Dumbassville
26×131 Posts |
I know if we could factor any residue mod Mp we probably wouldn't need the LL test but is this feasible for low p values:
a = LL residue mod Mp factor a and then eliminate k values based on k*p = (prime factors -1)/2 mod prime factors so if p is x mod prime factors k is y or z mod the prime factors ? edit: I'm just realizing this again probably Last fiddled with by science_man_88 on 2014-04-27 at 20:52 |
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#62 |
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Apr 2014
1678 Posts |
Something I was trying out today was running an LL just on the factors without the embedded 2, was doing some compares against the original LL
(Doing this via ^2, *2, -1 instead of ^2-2), seems to result in smaller residues to calculate overall but unfortunately an extra operation. 2*(2^2)-1=7 2*(7^2)-1=97 2*(97^2)-1=18817 |
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#63 |
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May 2013
East. Always East.
11×157 Posts |
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#64 |
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Romulan Interpreter
Jun 2011
Thailand
25B916 Posts |
Channeling my inner RDS, why is this stuff in the math forum?
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#65 |
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"Forget I exist"
Jul 2009
Dumbassville
26×131 Posts |
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#66 | |
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Jan 2014
2×19 Posts |
Quote:
1. Recall that every two prime-exponent Mersenne numbers are coprime (that is, they share no common factor greater than 1). What you noticed follows. or 2. Recall that if M(p) divides M(q) (p, q are odd primes) then (Also, unrelated, notice that p never divides |
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