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#45 |
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May 2004
New York City
10000100010112 Posts |
Ripping my posts or monograph to shreds
line-by-line with some negative comment for just about every line isn't possible to reply to. I generally write and think in paragraphs, the sentences are just components of which to for but. I think, but I'm not sure, that your objection is to my basic use of linear displacement (a vector) and velocity (also a vector) and acceleration (also a vector, btw) instead of distance (a scalar out of which displacement is defined and measured) and speed relative to light (a scalar from which the velocity vector is composed) if or and to from. Particle kinematics (and that's what we're discussing when the forces causing acceleration are ignored, i.e. not dynamics), is based on distance and speed, but in the 3-d world these must be elevated into dispacement and velocity, of by in from out. Perhaps you are objecting to the conclusions to be drawn from zero displacement of a RT, and not to the fact that I brought the vectors into the discussion of the Twin Puzzle? I didn't draw any conclusions myself in this thread which how when why the. |
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#46 |
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"Richard B. Woods"
Aug 2002
Wisconsin USA
22×3×641 Posts |
I'm accusing you not of failing to understand the Lorentz factor, but of overlooking the implication of the squaring of v in it.
Simple idealized example: Alice travels straight away from Earth at speed 0.99c for a year (Earth time), then travels back straight to Earth at speed 0.99c for a year (Earth time), arriving where she had left. (Assume that Alice is unharmed by the accelerations involved.) According to your logic, her total displacement is zero, and thus her total velocity is zero. but even though -0.99c is negative, (-0.99)2 is nonnegative, and thus produces the same (positive) Lorentz factor as (0.99)2. Her time/space dilations do NOT cancel out to zero, and all your arguments about "zero-total-force", "total velocity" and "total displacement" are irrelevant to the relativistic time dilation at the heart of the twin paradox. Last fiddled with by cheesehead on 2013-10-15 at 15:28 |
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#47 | |
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Bamboozled!
"๐บ๐๐ท๐ท๐ญ"
May 2003
Down not across
47×229 Posts |
Quote:
I'm still thinking about the case in which the universe is closed, whatever the topology. It could be a 4-ball at simplest or have any of a number of different topologies. Davar55's thesis doesn't distinguish between them. Last fiddled with by xilman on 2013-10-15 at 15:33 Reason: Add 2nd para |
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#48 |
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Sep 2009
40468 Posts |
In the closed universe case, what happens if the universe is expanding? The "easy" case is when the expansion is large enough to make it impossible to circumnavigate the universe (this allows you to duck all the interesting questions). If not would the traveler pass their starting point at the same speed as they left it (assuming they don't accelerate or decelerate in flight)?
Chris |
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#49 | |
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∂2ω=0
Sep 2002
Repรบblica de California
5·17·137 Posts |
Quote:
Question: Is "structural acceleration" due to cosmological exapnsion/contraction/distortion of the very spacetime fabric itself - that is, not induced by the presence of mass/energy - immune to this kind of IFR-ness test? For example, owing to the global spacetime expansion (purportedly) described by the BBC [the cosmological body of theory and observation, not the broadcasting network] we infer acceleration-away-from-us of distant objects based on their redshift* and assume ourselves part of this same globally-expansding spacetime fabric even though none of us "feels" any acceleration. If that indeed connotes non-IFR-ness, then is stands to reason that any global-spacetime topology which "curves back on itself" must similarly be non-inertial, hence any twin-paradox-style scenario would need to use the more general theory of relativity, not just the special. (I'm pretty sure I can look up the answer to the above question, but for now I found it a fun brain workout to just explore the issue without resorting to thought-displacing search tactics.) ----------- * Edit: Not merely based on the fact of redshifts alone but rather in the sense that redshifts, on average, increase with distance on cosmological scales. Last fiddled with by ewmayer on 2013-10-16 at 01:14 |
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#50 | |
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May 2004
New York City
5×7×112 Posts |
Quote:
and closedness as youall called it (no boundary and light would return through the other "side"), then the cosmological principle implies isotropy, hence I conclude the 3-d space is an essentially perfect "sphere" with a fixed fiinite radius R, and the skin (fourth spatial dimension) is much much thinner than R, so a 4-ball only works if the fourth dimension is weighted differently. But ignoring that detail, is there really another topology? I also wrote that 3-d space is everywhere Locally Euclidean, so the simplest toplogy is also the best description. |
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#51 | |
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Bamboozled!
"๐บ๐๐ท๐ท๐ญ"
May 2003
Down not across
101010000010112 Posts |
Quote:
If it helps you visualize what I mean, drop a dimension and think of a doughnut or a Klein bottle. |
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#52 |
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Jun 2003
7×167 Posts |
What is a self crossing loop? If you mean a trajectory which returns the particle to the same place, you would need to define "same place".
Last fiddled with by Mr. P-1 on 2013-12-05 at 14:04 |
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#53 | |
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May 2004
New York City
5·7·112 Posts |
Quote:
satisfies all physical phenomena and theory is most likely the correct description of the shape of the Universe. So we rule out the 4-d analog of a Klein bottle (what you called twisted space), and rule out the 4-d analog of a doughnut or torus (what you called a 3-torus), and taake the simplest shape that does the job, a 4-sphere (which within my explanation is just a 3-d sphere or 3-sphere Riemann-folded everywhere, and which because of the time dimension I labeled a super-hyper-sphere). |
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#54 |
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May 2004
New York City
5·7·112 Posts |
I understand Einstein envisioned a "cylindrical space-time". This was
I think only a 3-d conceptualization of 4-d space-time, with time being the axis of the cylinder. Do we know what 3-d spatial shape this was supposed to represent? Not a sphere, and not a cylinder. |
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#55 |
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Aug 2006
3·1,993 Posts |
I think the signature and topology are much more important than the shape. Key to Einsteinian physics is the use of the Minkowski metric, with signature (-1, +1, +1, +1) or the like. (Actually how this is represented seems to be something of a holy war which I don't want to enter, but the point is that one coordinate differs from the others in sign.)
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