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Old 2012-03-04, 17:52   #1
Zarck
 
Mar 2012

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Question Prime numbers Grid, to test an odd integer on 44

I believe to have found the means to test an odd integer on 44, to know if it is first. I do not know if this method already exists.

http://dl.dropbox.com/u/63176535/Premiers%20sites.pdf

*_*

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Old 2012-03-04, 18:29   #2
R.D. Silverman
 
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Quote:
Originally Posted by Zarck View Post
I believe to have found the means to test an odd integer on 44, to know if it is first. I do not know if this method already exists.

http://dl.dropbox.com/u/63176535/Premiers%20sites.pdf

*_*

Just what we need. Another ignorant Crank.
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Old 2012-03-04, 18:51   #3
science_man_88
 
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Quote:
Originally Posted by Zarck View Post
I believe to have found the means to test an odd integer on 44, to know if it is first. I do not know if this method already exists.

http://dl.dropbox.com/u/63176535/Premiers%20sites.pdf

*_*

Definitely will not be bowing to you as I really didn't get what you thought you found ( partly because of all the grammar issues). That and it sounds by what I can somewhat make out of what's said that you want to go back to factoring by dividing out composite factors ( even though you don't need to as the composites have prime factors).
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Old 2012-03-05, 02:52   #4
LaurV
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Quote:
Originally Posted by science_man_88 View Post
... I really didn't get what you thought you found ( partly because of all the grammar issues).
He found the wheel factorization method, particularized for number 44. He used Google Translator to translate his "article" into English (prime=first, from Latin, primus), which was quite an unfortunate choice.

Last fiddled with by LaurV on 2012-03-05 at 03:48
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Old 2012-03-05, 21:06   #5
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Quote:
Originally Posted by LaurV View Post
He found the wheel factorization method, particularized for number 44. He used Google Translator to translate his "article" into English (prime=first, from Latin, primus), which was quite an unfortunate choice.
I've looked at the link basically wheel factorization works on:

if a=\prod_{i=1}^{x} p(i)


a*n+p(d) is composite for all p(d) involved in a, and that p(d)*f is composite if f is not equal to 1.

Last fiddled with by science_man_88 on 2012-03-05 at 21:11
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Old 2012-03-06, 14:43   #6
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Quote:
Originally Posted by LaurV View Post
He found the wheel factorization method, particularized for number 44. He used Google Translator to translate his "article" into English (prime=first, from Latin, primus), which was quite an unfortunate choice.
I looked at it again couldn't the 9th step be reorder the matrix and repeat steps for the next prime.

Last fiddled with by science_man_88 on 2012-03-06 at 14:44
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