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#12 |
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"William"
May 2003
New Haven
2×7×132 Posts |
I think I see the misunderstanding. Bob is imagining that I marshaled factoring effort to find the N-1 factors, and that I am encouraging others to also spend their resources finding factors that are wanted only to make the N-1 proofs. I agree that would be pointless effort. But all I really did was click a few buttons and manually type the expression of a few algebraic factors. The needed factors were all small enough that the factordb "scan" buttons, which run a small amount of ECM, P-1, and P+1, provided sufficient factors to make the proof (It's also possible some of the factors were already in the factordb). At these current size ranges - 1200 to 2000 digits - I see lots of cases where adding the algebraic factors and the scan buttons does not complete a proof. I haven't been mentioning these, nor working on them.
So my question was "What should you do if you already know over 33% factorization of N-1?" I thought Bob was saying there is something better. But Batalov's question is "What should you do if you do NOT have 33% factorization?" Within the context of factordb, the answer to that question is currently "Primo." Last fiddled with by wblipp on 2011-11-09 at 05:46 |
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#13 | |
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Dec 2008
2638 Posts |
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#14 | |
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Nov 2003
22·5·373 Posts |
Quote:
Lehmer/Pomerance/Brillhart et.al. thm is fine. But, as you indicate, factoring efforts on N-1/N+1 are pointless. I am guilty of failing to convey this point. Note that APR-CL can take advantage of known factors of N+1/N-1 to speed its proof. I am unfamiliar with PRIMO. What method(s) does it employ? |
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#15 | |
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"Ben"
Feb 2007
351310 Posts |
Quote:
http://www.ellipsa.eu/public/primo/primo.html |
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#16 | |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
224068 Posts |
Quote:
> "...If you do not already have it, my validation script is here: > http://physics.open.ac.uk/~dbroadhu/cert/chgcertd.gp > \\ Coppersmith--Howgrave-Graham certificate tester, Version 0.8 > \\ David Broadhurst, 3 Mar 2006, with huge help from John Renze" |
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#17 | |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
10,753 Posts |
Quote:
I like it! Paul |
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#18 |
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"William"
May 2003
New Haven
2×7×132 Posts |
Browsing through the PRPs tonight, I found (10^1662*82-73)/9. N-1 is divisible by 10^1662-1. Sufficient factors were previously known to finish the proof.
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#19 |
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"William"
May 2003
New Haven
2×7×132 Posts |
Just to be clear - what I'm doing is looking the list of already-found PRPs in the factordb, searching for ones where a primality proof can be created easily. I do it because it's fun. I share them because I think other people will find it fun, too.
Last night I spotted (10^1470*4-7)/3. The N+1 shares the cyclotomic form 10^1470-1, which has many algebraic factors, many of which were already factored or quickly succumbed to the scan button. |
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#20 |
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Sep 2009
977 Posts |
I once proved the primality of (2^2617+1)/3 (788 digits), which appeared in the PRP list at the time, by N-1.
(2^2617+1)/3-1 has many small-ish factors, the unfactored part is currently a C322 (more than 450 digits smaller than the original C788 !). |
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#21 | |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
2×7×677 Posts |
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#22 |
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"William"
May 2003
New Haven
236610 Posts |
Today's proof is a cheat. N=(10^318*911+419)/73082460569797 is slightly larger the 300 digits. N-1 factored quickly with the scan buttons, having a largest factor a little below 300 digits. Factordb automatically proved the factor of N-1, enabling the proof of N.
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