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#45 |
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Aug 2006
597910 Posts |
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#46 | |
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Nov 2003
22·5·373 Posts |
Quote:
converge. Re-write it as: limit a-->oo integral from 1 to a of (1/floor(x) - 1/x)dx Call the kernel g(x). This is then: limit a-->oo [ integral from 1 to 2 g(x)dx + integral 2 to 3 g(x) dx + ......+ integral a-1 to a g(x) dx] What happens is that everything TELESCOPES...... It doesn't matter that one winds up subtracting two infinite quantities. One winds up with Major stupidity on my part. Last fiddled with by R.D. Silverman on 2011-06-06 at 01:59 Reason: typo |
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