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#1 |
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1976 Toyota Corona years forever!
"Wayne"
Nov 2006
Saskatchewan, Canada
532510 Posts |
I just noticed that the non-prime exponents between 1,000,000 and 1,005,000 have all been quadruple LL tested recently and many of them have had a couple dozen P-1 tests run with progressively larger B1/B2 combos all by the same user. i.e.
Code:
1001911 No factors below 2^61 P-1 B1=4200000, B2=4300000 Verified LL 373C by "David Slowinski" Verified LL 7EB3104CB7A0373C by "Terry S. Arnold" Verified LL 7EB3104CB7A0373C by "Brian J. Beesley" Verified LL 7EB3104CB7A0373C by "Rob_Dee" on 2009-12-23 - snip - History no factor from 2^60 to 2^61 by "Sturle Sunde" on 2009-02-15 - snip - History B1=1100000, B2=11000000 by "Rob_Dee" on 2009-12-15 History B1=1200000, B2=12000000 by "Rob_Dee" on 2009-12-15 History B1=1400000, B2=1500000 by "Rob_Dee" on 2009-12-16 History B1=1600000, B2=1700000 by "Rob_Dee" on 2009-12-17 History B1=1800000, B2=1900000 by "Rob_Dee" on 2009-12-18 History B1=2000000, B2=2100000 by "Rob_Dee" on 2009-12-19 History B1=2200000, B2=2300000 by "Rob_Dee" on 2009-12-20 History B1=2400000, B2=2500000 by "Rob_Dee" on 2009-12-21 History B1=2600000, B2=2700000 by "Rob_Dee" on 2009-12-22 History B1=2800000, B2=2900000 by "Rob_Dee" on 2009-12-23 History 7EB3104CB7A037__ by "Rob_Dee" on 2009-12-23 History B1=3000000, B2=3100000 by "Rob_Dee" on 2009-12-24 History B1=3200000, B2=3300000 by "Rob_Dee" on 2009-12-25 History B1=3400000, B2=3500000 by "Rob_Dee" on 2009-12-26 History B1=3600000, B2=3700000 by "Rob_Dee" on 2009-12-27 History B1=3800000, B2=3900000 by "Rob_Dee" on 2009-12-28 History B1=4000000, B2=4100000 by "Rob_Dee" on 2009-12-29 History B1=4200000, B2=4300000 by "Rob_Dee" on 2009-12-30 If he is choosing to do these assignments - it's a free country. If, on the other hand, he doesn't understand the testing process he may not be aware that he is essentially doing a lot of unnecessary work. Last fiddled with by petrw1 on 2009-12-30 at 20:32 Reason: spelin' |
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#2 |
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"Mark"
Feb 2003
Sydney
3×191 Posts |
I wonder how many factors they've found? Unfortunately, although PrimeNet tells us who did the unsuccessful factoring efforts, it does not tell us who was successful and found a factor.
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#3 |
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"Lucan"
Dec 2006
England
2·3·13·83 Posts |
Love the risquee title of this thread
Last fiddled with by davieddy on 2009-12-31 at 04:31 |
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#4 | |
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Mar 2010
Morgantown, WV
29 Posts |
Quote:
As I know very little about the math involved in Prime95, and understand even less, it seems to me that P-1 testing is successful very rarely due to the unique properties a factor would have to have in order to be found by it: to have all factors of the factor - 1 be less than B1, or only one between B1 and B2. I don't know what the success rate has been for GIMPS's P-1 efforts finding factors, but I expect it to be less than 5%, and not just because bounds are picked which provide the best time-saving and often result in having probabilities of success of 6% and lower. I factored the factors of the 116 largest factors reported to PrimeNet in order to see what bounds would have discovered them, only 3 had largest P-1 factor less than 9 digits in size. I do realize, however, that P-1 will find any factor of an exponent as long as the factor's factors meet the P-1 criteria, and smaller factors probably are more-likely to do so. I really did the test I did to see if P-1 was at all a good idea to try to find the large factor waiting to be found for M1061. Still, it seems to me that using P-1 to find factors for M999959 and M1000003 is a bad idea, but by incrementing the search as he is Rob is at least building a cummulative effort and perhaps making the best of a bad situation. What say you experts, is Rob onto something or using good cycles in a not-so-good way? While I have your "ears" on P-1, would you rather a P-1 tester use a large B1 and let B2=B1, or should one use the recommended B1 and B2 for an exponent? Best of luck to Rob! |
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#5 | ||||
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Apr 2007
Spessart/Germany
2×83 Posts |
Quote:
But was it a bad idea? This depends on what he wanted. To find a factor of the Mersenne-number it was a bad idea. To get many 'GHz-days' on the P-1 top-producer list it was a 'good' idea. It is possible to copy the save-file of prime95 while doing a stage 2 of a P-1 factoring. After finishing the P-1 and posting the result, you can re-copy the save-file and start a P-1 with larger B1 (but only a little bit larger as before). Now you only need to do a stage 1 from the old B1 up to the new B1 which will save some time. But after finishing the new P-1 you will get the same amount of 'GHz-days' from the server as if you did the new P-1 completely. There were already some discussions in some threads about this problems, and I think in the meantime George Woltman is looking for such 'small expandations' of P-1 and subtracts the 'bad GHz-days' Quote:
A P-1 factoring with B1,B2 'knows' about the congruence A ECM curve with the same boundaries B1,B2 doesn't 'know' anything about this congruence. Thus a P-1 with B1,B2 is the fastetst ECM-curve with this boundaries and it is the curve with the highest probability to find a factor. But it is only *one* curve, it is not needed to do a P-1 with nearly the same boundaries on a Mersenne-number (or another number) again. If I want to make a new P-1 on a Mersenne-number I'm choosing at least new B1 >= 4* old B1 (most times B1(new)=10*B1(old)) and B2 as large as possible... Quote:
Quote:
greetings Matthias |
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#6 |
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Mar 2010
Morgantown, WV
29 Posts |
Matthias, I do not know how to adequately thank you for the insight and information you have provided me, both on this thread and my M4219 thread. I am always worried about being skewered by Dr. Silverman as well as the other very knowledgable people on this forum because I don't know enough to even form the most basic questions in most cases, but you come along and offer in depth yet easy to follow explanations and do so with a friendly, helpful, and encouraging manner. Truly, thank you.
I have had a busy morning and my brain is even less able to try to understand what you have said, but I will continue trying and hope I will not lose your patience should I have additional questions. Thank you again. |
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