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#12 |
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"Forget I exist"
Jul 2009
Dumbassville
26×131 Posts |
according to the equation the final mass must be about 3.57% of the original mass assuming no payload this has the full stage as about 20.22% of the original mass. assuming this is even close the answer to the question about equal mass per stage is trivially no even to a dummy like me.
never mind I actually read more lol. first stage = 88-89%of total mass ? Last fiddled with by science_man_88 on 2010-07-10 at 02:14 |
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#13 |
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Oct 2007
Manchester, UK
22×3×113 Posts |
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#14 | |
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"Forget I exist"
Jul 2009
Dumbassville
838410 Posts |
Quote:
and i also state what I believe to be the percentage of the weight to be the first stage. oh sorry that's the mass of the fuel in the first stage by my guess i realize that now lol so 88-89% total mass is in the fuel of the first stage violating your limit. but if you look at it 10000/3000=ln(100/100-x) which if i did the math correctly means e^(10/3) = (100/100-x) which makes the denominator between 100-88 and 100-89 which violates your rule. Last fiddled with by science_man_88 on 2010-07-10 at 11:31 |
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#15 |
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Oct 2007
Manchester, UK
22·3·113 Posts |
OK, some clarification. In the first example I posted, with each stage having a fuel mass 85% and dry mass 15%, that means each stage taken individually.
The minimum mass of the rocket is given when each stage imparts a quarter of the desired delta-v to the remaining rocket stack, 2500 m/s, and these are the masses of each stage: Code:
stage 1: dry mass = 7939.2 kg propellant mass = 44988.8 kg total mass = 52928.0 kg stage 2: dry mass = 2658.2 kg propellant mass = 15063.2 kg total mass = 17721.4 kg stage 3: dry mass = 890.0 kg propellant mass = 5043.5 kg total mass = 5933.5 kg stage 4: dry mass = 298.0 kg propellant mass = 1688.7 kg total mass = 1986.7 kg complete rocket stack: payload = 1000 kg dry mass = 12785.4 kg propellant mass = 66784.1 kg total mass = 79569.6 kg Code:
delta-v = v_e * ln( m0 / m1 ) delta-v = 3000 * ln( 79569.6 / 34580.8 ) delta-v = 3000 * ln( 2.3009763 ) delta-v = 2500 m/s For the rocket as a whole, the propellant accounts for 66784.1 / 79569.6 * 100 = 83.93% of the mass. The first stage accounts for 52928.0 / 79569.6 * 100 = 66.52% of the mass of the rocket, ths number isn't really relevant, but you mentioned it in your posts as being 88 to 89% of the mass. |
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#16 | |
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"Forget I exist"
Jul 2009
Dumbassville
203008 Posts |
Quote:
I don't see how you got the masses I know about the percentages a bit care to explain it more ? Last fiddled with by science_man_88 on 2010-07-10 at 17:27 |
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#17 |
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Oct 2007
Manchester, UK
22·3·113 Posts |
Well now you know you know, so go for it. Here's a big hint.
Look at the delta-v for each stage individually, ignoring payload and other stages. Compare this to the delta-v the stage provides in the actual rocket. The data I uploaded previously will help here. |
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#18 |
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"Forget I exist"
Jul 2009
Dumbassville
26×131 Posts |
no I don't and second you realize both m0 and m1 can be scaled down by 16 each at least by my math that would mean it's not the minimum(oh wait you'd need scaled payload(62.5 kg isn't worth it)).
Last fiddled with by science_man_88 on 2010-07-10 at 18:17 |
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#19 |
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Oct 2007
Manchester, UK
22·3·113 Posts |
When finding the masses, start at the top of the rocket, in other words, figure it out from the last stage first. Using the first example again, you know the payload is 1000 kg, you know the stage should impart 2500 m/s, and you know if has a fuel fraction of 85% and an exhaust velocity of 3000 m/s, so use the rocket equation:
Code:
delta-v = v_e * ln(m0 / m1) 2500 = 3000 * ln((m+1000) / (0.15m+1000)) 5/6 = ln((m+1000) / (0.15m+1000)) e^(5/6) = (m+1000) / (0.15m+1000) (0.15m+1000)e^(5/6) = (m+1000) 0.15m*e^(5/6) + 1000e^(5/6) = m + 1000 1000e^(5/6) - 1000 = m - 0.15m*e^(5/6) 2300.976 - 1000 = m - 0.345m 1300.976 = 0.655m m = 1300.976 / 0.655 m = 1986.7 kg The important part is finding the correct values for m0 and m1. m0 is the full mass of the stage PLUS the mass of any stages higher up and the mass of the payload. m1 is the empty mass of the stage plus all that other stuff too. That is why you need to start at the top and work down, because you need to find the masses of the higher stages first and include them in the calculations for the lower stages. |
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#20 | |
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"Forget I exist"
Jul 2009
Dumbassville
26×131 Posts |
Quote:
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#21 | |
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Apr 2010
2×3×52 Posts |
Quote:
Define Mi as the dimensionless total mass at the beginning of stage i: M1 = m1+m2+m3+m4+1 M2 = m2+m3+m4+1 M3 = m3+m4+1 M4 = m4+1 M5 = 1 Thus, for optimization purposes, you are looking for a stationary point of M1+lambda*( ln(M1/(0.15M1+0.85M2)) +ln(M2/(0.15M2+0.85M3)) +ln(M3/(0.15M3+0.85M4)) +ln(M4/(0.15M4+0.85)) -10/3) with respect to M1...M4, and lambda. Rewrite further by defining the mass ratios Xi = M(i+1)/Mi and the additional constraint M1 X1 X2 X3 X4 = 1. Abbreviate the core expression for the per-stage delta-v as f(Xi) = -ln(0.15+0.85Xi). Now you are looking for zero partial derivatives of M1 + lambda * (f(X1)+f(X2)+f(X3)+f(X4)-10/3) + mu * (M1 X1 X2 X3 X4 - 1) with respect to M1, X1...X4, lambda and mu. We have two constraints for M1, X1...X4, and therefore there are two corresponding Lagrange multipliers lambda and mu. Note that this to-be-optimized expression is symmetric in X1...X4. Looking for a zero of the partial derivative with respect to M1 gives 1 + mu X1 X2 X3 X4 = 0, hence mu = -1 / (X1 X2 X3 X4). Looking for a zero of the partial derivative with respect to Xi yields lambda * f'(Xi) + mu M1 X1 X2 X3 X4 / Xi = 0, i.e. -lambda * 0.85/(0.15+0.85Xi) - M1/Xi = 0, thus 0.85Xi/(0.15+0.85Xi) = -M1/lambda (assuming nonzero lambda because otherwise its constraint would not be effective) We could go on further, but you already see that all Xi must have the same value. Consequently, all f(Xi) and thus all delta-v-per-stage must have the same value. This generalizes to any number of stages, as long as exhaust-v and propellant-mass-percentage are the same for each stage. Last fiddled with by ccorn on 2010-07-11 at 06:02 |
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#22 | |
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"Forget I exist"
Jul 2009
Dumbassville
26×131 Posts |
I was going to reopen with a speed of light test but now I can't see how the highlighted steps work out.
Quote:
Last fiddled with by science_man_88 on 2011-01-11 at 15:38 |
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