how to know if my ideas didnt tought before?

[blob100]

Originally Posted by R.D. Silverman

I gave an example.



OK. So, if this is your notation, you need to express 'a' as a function of
m. a depends on m.

For m natural numbers.
a equals to 1 or m-1.
Further more: if m=4n or 5n we have a=1.
For n>1, natural number.

[R.D. Silverman]

Originally Posted by blob100

For m natural numbers.
a equals to 1 or m-1.
Further more: if m=4n or 5n we have a=1.

No. Not quite.

e.g. let m = 8. The units are 1,3,5,7. Their product mod 8 is 7. This
clearly isn't 1.

let m = 10, the units are 1,3,7,9. Their product mod 10 is 9. This clearly
isn't 1.

[blob100]

Originally Posted by R.D. Silverman

No. Not quite.

e.g. let m = 8. The units are 1,3,5,7. Their product mod 8 is 7. This
clearly isn't 1.

let m = 10, the units are 1,3,7,9. Their product mod 10 is 9. This clearly
isn't 1.

Keyboard writing mistake, I wanted to write n>2.

[R.D. Silverman]

Originally Posted by blob100

Keyboard writing mistake, I wanted to write n>2.

Now you are getting ridiculous. You are grossly incorrect.

Don't you bother checking your answers by simple example???

[blob100]

Originally Posted by R.D. Silverman

Now you are getting ridiculous. You are grossly incorrect.

Don't you bother checking your answers by simple example???

Every natural number m, have a number a equals 1 or m-1 (for a, d(m) defined before).
For evey m with a residue class m-1, a=m-1.

Example:
m=16.
3*5=b(mod 16)
b=3*5=16-1.
And further more:
d(m)=a(mod 16)
a=16-1.

Where b is the residue class of (3,5).

[R.D. Silverman]

Originally Posted by blob100

Every natural number m, have a number a equals 1 or m-1 (for a, d(m) defined before).

This is correct. Either a = 1 or a = -1 = m-1 mod m However:

(1) You need to justify your answer. How did you get it?
Show your work. It is not sufficient to simply assert the answer.

(2) You need to determine which m give the answer 1,
and which m give the answer -1.

Hint: This is closely related to a problem we already looked at. Think
about the units that are their own inverse.

[jyb]

Originally Posted by R.D. Silverman

Now you are getting ridiculous. You are grossly incorrect.

Don't you bother checking your answers by simple example???

Sometimes people just make mistakes. It isn't always a sign that they're feeble-minded. For example:

Originally Posted by R.D. Silverman

e.g. let m = 8. The units are 1,3,5,7. Their product mod 8 is 7. This
clearly isn't 1.

[R.D. Silverman]

Originally Posted by jyb

Sometimes people just make mistakes. It isn't always a sign that they're feeble-minded. For example:

Students of mathematics need it drilled into them that they need to
check their answers.

[3.14159]

Originally Posted by bsquared

Assuming the poster is ESL (english as a second language), I would hold them to what you say for formal publication. Even then, it does not always happen: I've read numerous journal articles in which ESL authors didn't quite hit the mark but nonetheless were understandable and were published.

Discussion here should be a little more relaxed than formal publication standards, IMO.

He attacks anyone, even kids apparently. LOL. Having the moron on the ignore list is the best decision that I ever made. The sad guy even goes after children.. how tragic...

[flouran]

Originally Posted by 3.14159

He attacks anyone, even kids apparently. LOL. Having the moron on the ignore list is the best decision that I ever made. The sad guy even goes after children.. how tragic...

I like your humor.

[3.14159]

Originally Posted by blob100

The number 431is a good example for a non p (as I explained),
it is like putting 4 as a prime number because it is a natural number as a prime number is.
The number I told to put were prime numbers that are the factors of mersenne numbers with an odd exponential.
(I think you tought these are just prime numbers).
p isn't a normal prime number, it is a number as:
7,23,31,83...
You can see that 23's smallest odd factor that agrees 2^e(p-1)>p is 11 because 23's factors are 2,11.
83 and 7 are the same as 23.
31 is a more interesting,
31-1=30, and the smallest odd factor that agrees 2^e(p-1)>p is 5.
17 isn't a p number as I explained it is, because it's smallest factor that agrees 2^e(p-1)>p isn't an odd number (8 isn't an odd number).
Please read what I write before saying things are false.

431 is prime. Point debunked.

Proofs:
431/2 =/= Integer
431/3 =/= Integer
431/5 =/= Integer
431/7 =/= Integer
431/11 =/= Integer
431/13 =/= Integer
431/17 =/= Integer
431/19 = Integer
sqrt(431) = 20
431 is prime
QED