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Old 2010-04-18, 01:21   #1
odin
 
Apr 2010

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Default What minimum exponent would give 100M digit prime?

Hello All,

What minimum exponent value would give a 100M digit prime?

Also is there a calculator on the internet or that I could download that could give me the specific number that any exponent I use in the formula 2^P - 1?

Like to calculate the value of:

2^49254458 - 1?

Of course my computer's calculator gives infinity!!!!!

Thanks.

Last fiddled with by odin on 2010-04-18 at 01:22
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Old 2010-04-18, 01:24   #2
CADavis
 
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http://mersenne-aries.sili.net/digits.php calculate number of digits from an exponent

i think it something above 332,000,000 for the exponent to give a 100M digit mersenne number.
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Old 2010-04-18, 01:28   #3
odin
 
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Quote:
Originally Posted by CADavis View Post
http://mersenne-aries.sili.net/digits.php calculate number of digits from an exponent

i think it something above 332,000,000 for the exponent to give a 100M digit mersenne number.
Thanks. You are right. I don't think I will be winning that prize. lol
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Old 2010-04-18, 02:22   #4
lfm
 
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Quote:
Originally Posted by CADavis View Post
http://mersenne-aries.sili.net/digits.php calculate number of digits from an exponent

i think it something above 332,000,000 for the exponent to give a 100M digit mersenne number.
Its pretty easy if you have a proper calculator. Just 1e6*ln(10)/ln(2)=3321928.09 or so.
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Old 2010-04-18, 05:58   #5
Uncwilly
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332192831 is the first prime that is 100 M digits.
There is a thread for those that TF'ing those in the range.
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Old 2010-04-18, 11:05   #6
10metreh
 
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Quote:
Originally Posted by Uncwilly View Post
332192831 is the first prime that is 100 M digits.
[pedant]No, it's the first prime p such that log10(2p-1) > 99,999,999.[/pedant]
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Old 2010-04-18, 11:09   #7
lfm
 
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Quote:
Originally Posted by lfm View Post
Its pretty easy if you have a proper calculator. Just 1e6*ln(10)/ln(2)=3321928.09 or so.
oops should be 1e8!
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Old 2010-04-18, 13:57   #8
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Quote:
Originally Posted by 10metreh View Post
[pedant]No, it's the first prime p such that log10(2p-1) > 99,999,999.[/pedant]
You didn't see my [lazy shorthand][/lazy shorthand]?
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