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Old 2004-01-14, 06:32   #1
michael
 
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Can you figure out the next number in this 'trivial' sequence?

10, 11, 12, 13, 14, 15, 16, 17, 20, 22, 24, 31, 100, 121, ?

-michael
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Old 2004-01-14, 16:51   #2
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10000
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Old 2004-01-19, 18:29   #3
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base 16, base 15, base 14, ... next in sequence is base 2
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Old 2004-01-20, 03:48   #4
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http://www.research.att.com/cgi-bin/...i?Anum=A008713
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Old 2004-01-25, 11:19   #5
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Quote:
Originally Posted by michael
Can you figure out the next number in this 'trivial' sequence?

10, 11, 12, 13, 14, 15, 16, 17, 20, 22, 24, 31, 100, 121, ?

-michael
Dear Michael,
please explain Dweiks solution.
Mally
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Old 2004-01-25, 13:05   #6
xilman
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Quote:
Originally Posted by mfgoode
Dear Michael,
please explain Dweiks solution.
Mally
It's the value (1+1+1+1)^(1+1) expressed in radices descending to
the value (1+1+1) and you have to express the final value in the radix (1+1).

How about that for a radix-independent answer?


Paul
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Old 2004-01-25, 14:53   #7
michael
 
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(10)hexadecimal=(11)15=(12)14=(13)13=(14)12=(15)11=16decimal=(17)9=(20)octal=(22)7=(24)6=(31)5=(100)4=(121)3=(10000)binary

General:
(abcde)n=(a*n4+b*n3+c*n2+d*n1+e*n0)decimal

Hope this answers your question Mally,

-michael
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Old 2004-01-25, 16:23   #8
mfgoode
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Quote:
Originally Posted by xilman
It's the value (1+1+1+1)^(1+1) expressed in radices descending to
the value (1+1+1) and you have to express the final value in the radix (1+1).

How about that for a radix-independent answer?


Paul
Thanks Paul. I still will have to put pen to paper and fathom it out.
Mally.
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Old 2004-01-25, 16:25   #9
mfgoode
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Quote:
Originally Posted by michael
(10)hexadecimal=(11)15=(12)14=(13)13=(14)12=(15)11=16decimal=(17)9=(20)octal=(22)7=(24)6=(31)5=(100)4=(121)3=(10000)binary

General:
(abcde)n=(a*n4+b*n3+c*n2+d*n1+e*n0)decimal

Hope this answers your question Mally,

-michael
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Old 2004-01-25, 16:30   #10
mfgoode
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Thanks Michael.Still I need a more elementary clarfication.
Mally
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Old 2004-01-25, 16:40   #11
michael
 
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Take for instance (14)12=(1*121+4*120)decimal=12+4=16

or (121)3=(1*32+2*31+1*30)decimal=9+6+1=16

other way round: 16=1*24+0*23+0*22+0*21+0*20 so 16=(10000)2 or binary

-michael
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