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View Poll Results: When will the first 10 million digit prime number be found?
0, I am not currently running gimps, there is no client for my PDA. 3 3.30%
1, I believe GIMPS is a good use of my time, but am not so in to it as a hobby. 24 26.37%
2-3, I have a small home network, or have my home and work machine on gimps. 25 27.47%
4-6, I have a small network at home/a few machines at work I admin. 24 26.37%
7-15, It is an obcession, true, but one I dreadfully enjoy. This is my mark on history. 15 16.48%
Voters: 91. You may not vote on this poll

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Old 2002-10-21, 06:15   #1
Deamiter
 
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Sep 2002

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Default when will the 10M Digit prime be found?

Yeah... so I was bored. Personally, though, I think it'll be sometime in December when my test finishes... :D
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Old 2003-08-25, 08:41   #2
hyh1048576
 
Jun 2003

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I reply it so it can get to the top of the forum :) ......And it's time to discuss it again :D
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Old 2003-08-25, 13:01   #3
alienz
 
Jun 2003

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Should we not forget the small ones and go straight for primes M10million. That is where the money is. By the time we get there Piv 4ghz machines will be the norm.
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Old 2003-08-25, 14:17   #4
nomadicus
 
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Jan 2003
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My belief is that we will discover M40 and M41 before the 10 million prime (assuming that M39 remains as is). Of course that's the current reading into my crystal ball. Hmmm.... I better get some cleaner out and polish that thing just in case.
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Old 2003-08-25, 14:20   #5
cheesehead
 
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"Richard B. Woods"
Aug 2002
Wisconsin USA

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Anyone care to prove that there is a ten-million-digit prime to be found?

That is, present a proof that not all integers with exactly 10,000,000 decimal digits (i.e., N such that N is in Z and 10^9,999,999 < N < 10^10,000,000) are composite. Who can present the most elegant proof?

Proof by (counter-)example will be considered the most elegant method. :)
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Old 2003-08-25, 17:34   #6
Orgasmic Troll
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Jul 2003

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let n = 10^9,999,999

there exists a prime p such that n < p < 2n (chebychev's theorem)

2 * 10^9,999,999 has 10 million digits
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Old 2003-08-25, 19:57   #7
cheesehead
 
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That's the one I had in mind, though I didn't recall the theorem's being named after Chebychev. By the same method, for every k > 0 there are at least three primes with k decimal digits.

Is there another elegant proof?
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Old 2003-08-25, 21:04   #8
ewmayer
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Sep 2002
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A related question (albeit one of a probabilistic nature): what is the expected number of primes having exactly 10,000,000 decimal digits?
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Old 2003-08-25, 22:59   #9
apocalypse
 
Feb 2003

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Well, if we can assume (without proof :) ) that E[pi(n)], the expected number of primes less than n, is n / ln(n), then the short answer is:

E[pi(n)] = 10^(10^7)/ln(10^(10^7)) - 10^(10^7 - 1)/ln(10^(10^7 - 1))

or, more coarsely, about 3.9 * 10^(10^7 - 8 )

Unelss my math is wrong, in which case it will no doubt be corrected by another poster.
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Old 2003-08-26, 02:54   #10
E_tron
 
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Sep 2002
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I'm thinking the first 10million digit mersenne prime is above M45 . I just kind of did a curve of the past primes and there location on a number line :D .

According to my little unproved theory, the next mersenne prime is around M25 :D .
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Old 2003-08-26, 13:07   #11
Uncwilly
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Shouldn't that be 25Mnot M25? M25 Has been already found.
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