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#1 |
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Nov 2002
Vienna, Austria
41 Posts |
[pre]\/ \/ \/ - \/ \/ \/ \ /
/\ /\ /\ - /\ /\ /\ \/[/pre] Obviously these matches show XXX=XXXV. What's the minimum number of matches to be re-arranged? In other words: how many moves are necessary to get a correct equation? 1) equations have an equal sign (=) 2) "move" does NOT mean "throw away" Good luck
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#2 |
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Jun 2003
The Texas Hill Country
32·112 Posts |
I'll open the bidding with 8.
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#3 |
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"Mark"
Apr 2003
Between here and the
2×32×353 Posts |
I can do it in four, but since I haven't figured out how to do that shadowing thing yet, I'll post if nobody can beat it.
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#4 |
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Nov 2002
Vienna, Austria
41 Posts |
Okay folks ... solution is less than 4 and no correct post or pm seen yet
The shadowing is done by the SPOILER-tag {SPOILER] {FONT=courier new] often useful to have a font like that {/FONT] {/SPOILER] becomes [FONT=courier new] often useful to have a font like that [/FONT] if and only if you use the correct left brackets [ instead of the false ones { I used in the example above, because I don't know how to code a [ here ...
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#5 |
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Dec 2003
Belgium
5×13 Posts |
2 replacements (if you use 4 matches for each number as u wrote them down)
-michael Last fiddled with by michael on 2004-01-20 at 17:27 |
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#6 |
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Aug 2003
Upstate NY, USA
2×163 Posts |
2 is my best, but since he said he had no correct PMs as of 12:36 and I PMed him that at 10:06 idk.
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#7 | ||
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Jan 2004
Europe/Austria
3 Posts |
hi,
what about this: just touching the last 'X' of the equation and make a 'V' out of it: XXX = XXVV If you put the matches initially wide enough apart, you can even manage it with touching just one of the two matches in the last 'X': before: Quote:
Quote:
cheers uli Last fiddled with by ulikilian on 2004-01-22 at 15:17 |
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#8 |
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6809 > 6502
"""""""""""""""""""
Aug 2003
101×103 Posts
7·23·61 Posts |
XXVV that ain't "proper" Roman Numerals AFAIK
Last fiddled with by Uncwilly on 2004-01-22 at 21:14 |
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#9 |
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Sep 2002
6010 Posts |
What about 0 moves? \/ \/ \/ - \/ \/ \/ \ / /\ /\ /\ - /\ /\ /\ \/ second x is a multiply, last x is a multiply. |
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#10 |
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Nov 2002
Vienna, Austria
4110 Posts |
First correct answer by ASDF !!!
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#11 | |
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Jun 2003
The Texas Hill Country
32×112 Posts |
Quote:
Besides, it is not generally acceptable to use the same symbol to be both an operator and an operand. |
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