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Old 2004-01-20, 13:19   #1
koal
 
Nov 2002
Vienna, Austria

41 Posts
Default 30 = 35 ???

[pre]\/ \/ \/ - \/ \/ \/ \ /
/\ /\ /\ - /\ /\ /\ \/[/pre]

Obviously these matches show XXX=XXXV. What's the minimum number of matches to be re-arranged?

In other words: how many moves are necessary to get a correct equation?

1) equations have an equal sign (=)
2) "move" does NOT mean "throw away"

Good luck
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Old 2004-01-20, 15:05   #2
Wacky
 
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Jun 2003
The Texas Hill Country

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I'll open the bidding with 8.


\/ \/ \ / - \/ \/ _|_ \ /
/\ /\ \/ - /\ /\ | \/
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Old 2004-01-20, 15:46   #3
rogue
 
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"Mark"
Apr 2003
Between here and the

2×32×353 Posts
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I can do it in four, but since I haven't figured out how to do that shadowing thing yet, I'll post if nobody can beat it.
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Old 2004-01-20, 16:36   #4
koal
 
Nov 2002
Vienna, Austria

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Okay folks ... solution is less than 4 and no correct post or pm seen yet

The shadowing is done by the SPOILER-tag

{SPOILER]
{FONT=courier new]
often useful to have a font like that
{/FONT]
{/SPOILER]

becomes


[FONT=courier new]
often useful to have a font like that
[/FONT]


if and only if you use the correct left brackets [ instead of the false ones { I used in the example above, because I don't know how to code a [ here ...

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Old 2004-01-20, 17:23   #5
michael
 
Dec 2003
Belgium

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2 replacements (if you use 4 matches for each number as u wrote them down)
-michael

Last fiddled with by michael on 2004-01-20 at 17:27
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Old 2004-01-20, 17:44   #6
tom11784
 
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Aug 2003
Upstate NY, USA

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2 is my best, but since he said he had no correct PMs as of 12:36 and I PMed him that at 10:06 idk.

\/ \/ \/ - \/ \/ \/ / |
/\ /\ /\ - /\ /\ /\ / |
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Old 2004-01-22, 15:12   #7
ulikilian
 
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Jan 2004
Europe/Austria

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Default

hi,
what about this:
just touching the last 'X' of the equation and make a 'V' out of it:
XXX = XXVV

If you put the matches initially wide enough apart, you can even manage it with touching just one of the two matches in the last 'X':

before:

Quote:
\/ \/ \/ - \/ \/ \/ \ /
/\ /\ /\ - /\ /\ /\ \/
after:

Quote:
\/ \/ \/ - \/ \/ \ /\ /
/\ /\ /\ - /\ /\ \/ \/
or is it all NOT what you wanna here?

cheers
uli

Last fiddled with by ulikilian on 2004-01-22 at 15:17
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Old 2004-01-22, 21:13   #8
Uncwilly
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XXVV that ain't "proper" Roman Numerals AFAIK

Last fiddled with by Uncwilly on 2004-01-22 at 21:14
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Old 2004-01-23, 02:45   #9
asdf
 
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Sep 2002

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What about 0 moves?

\/ \/ \/ - \/ \/ \/ \ /
/\ /\ /\ - /\ /\ /\ \/

second x is a multiply, last x is a multiply.
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Old 2004-01-23, 15:43   #10
koal
 
Nov 2002
Vienna, Austria

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First correct answer by ASDF !!!

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Old 2004-01-23, 16:31   #11
Wacky
 
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Jun 2003
The Texas Hill Country

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Quote:
Originally Posted by koal
Obviously these matches show XXX=XXXV
So your statement of the problem is not rigorous.

Besides, it is not generally acceptable to use the same symbol to be both an operator and an operand.
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