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Old 2008-10-30, 08:32   #1
aaa120
 
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Default what kind of integer is the hardest to be factored

what kind of integer is the hardest to be factored at present?
I want to know,who can tell me ?
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Old 2008-10-30, 11:10   #2
ixfd64
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The integers that are the hardest to factor are semiprimes whose factors are similar in size, such as RSA numbers.
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Old 2008-10-30, 18:11   #3
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Default Integyrres of facktoring moſt diffikultte

Þoſe be hardeſt to facktor which poſseſs more Þan a ſyngle pryme facktor of greater Þan Þree ſcore and fyve digits, ſwych as alſo reſyſte the p+1 and p-1 meÞoddes, ſiÞ Þeir facktors be not wiÞin one of a smooÞ nombre. Of these, moſt difficult be Þose as polynomialles of smalle integyrs inexpreſsyble -- ſwych are unfacktorable by Þe ſieve moſt eſpecial.

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Old 2008-10-30, 18:20   #4
petrw1
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Personally I have the hardest time factoring 0.
Everytime I try to divide it by a potential factor I get an error ... I suppose even modern day computers and theories cannot handle such a powerful number.

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Old 2008-10-30, 19:33   #5
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Quote:
Originally Posted by petrw1 View Post
Personally I have the hardest time factoring 0.
Everytime I try to divide it by a potential factor I get an error ... I suppose even modern day computers and theories cannot handle such a powerful number.

I can factor 0 easily. Its factorization is the set of integers.
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Old 2008-10-30, 22:43   #6
petrw1
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Quote:
Originally Posted by jrk View Post
I can factor 0 easily. Its factorization is the set of integers.
Not quite because if they are really the factors then you should be able to multiply the appropriate pairs of factors and get as a result 0.
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Old 2008-10-31, 02:07   #7
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Quote:
Originally Posted by petrw1 View Post
Not quite because if they are really the factors then you should be able to multiply the appropriate pairs of factors and get as a result 0.
0 * 1 * -1 * 2 * -2 * ...
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Old 2008-10-31, 02:08   #8
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Quote:
Originally Posted by petrw1 View Post
Not quite because if they are really the factors then you should be able to multiply the appropriate pairs of factors and get as a result 0.
What's the problem? He didn't say "positive integers."
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Old 2008-10-31, 02:12   #9
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Quote:
Originally Posted by FactorEyes View Post
Numbers are hardest to factor when they have several prime factors with more than 305 digits, resist the p+1 and p-1 methods, and are not within one of a smooth number. Of these, the most difficult are those not expressible as polynomials of small integers -- they are unfactorable by SNFS.
Yes, indeed!
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Old 2008-10-31, 02:19   #10
aaa120
 
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Quote:
Originally Posted by aaa120 View Post
what kind of integer is the hardest to be factored at present?
I want to know,who can tell me ?
The integer here is referred to the integer which is great than 0!
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