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#1 |
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Nov 2003
22×5×373 Posts |
It appears that Greg and Bruce have some very large resources
available to them. (very nice!) and are tackling some very hard numbers. This is terrific. Although I'd like to see them do some of the first few holes, I understand their reasons for not tacking the current "wanted" lists and it seems quite reasonable. I'd like to see an effort to finish base 2 to 800 bits. I am currently sieving 2,1101+ (1/3 sieved) and will then do 2,1104+. After that, I will sieve 2,1538M. [but may need help with the LA; my biggest machine has only 2G]. The remaining 2 numbers less than 800 bits are 2,799+ (SNFS), 2,1538M (I will do; SNFS), 2,1586L (GNFS!), 2,1598L (??), and 2,1598M (GNFS), I exclude for the moment the base 2 numbers with composite exponents above 800 bits that have a usable algebraic factor. I will do some of these eventually. The Query: An interesting question. Is 2,1598L C171 (799 bits by SNFS) easier by SNFS or GNFS? It is close. I suspect the former. Also an observation: Base 11 has been relatively neglected.... |
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#2 |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
47·229 Posts |
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#3 |
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(loop (#_fork))
Feb 2006
Cambridge, England
642210 Posts |
Base 11 is a bit neglected, but 5,331[+-] are both only just over 768 bits and look like reasonable personal-snfs targets; also 7,277[+-] at 778 bits.
2,821- is the only number on the wanted list that's not claimed, and is I suppose a natural target for mersenneforum; a bit more work than 3+512, but 3+512 doesn't seem to have been a serious strain. I've reserved it with Sam, and will do some experimental sieving to get parameters tonight. x^6-2 must be the right polynomial, though I'm surprised to find that by at least one measure ( Last fiddled with by fivemack on 2008-05-08 at 15:40 |
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#4 | |
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Jun 2005
lehigh.edu
210 Posts |
Quote:
Code:
11,251- c208 Childers/Dodson 2,1101+ c211 Silverman ... 2,788+ c219 NFSNET 6,313- c227 NFSNET 10,241- c229 NFSNET still a c258, but ecm hapened to it; so we're doing the c208 anyway). The 788+ was a last minute suggestion from Sam, but it was clearly too small, under two weeks of sieving (with lots of turn-around effort for NFSNET). We're doing 10,241- c229, difficulty 241 mostly as a warm-up (and base-10 affirmative action), difficulty approaching 245 seems to be a more likely range. Note also that NFSNET did do two of the last three under 768-bits; so it's not like we haven't been doing our share of the 1st five holes. As you've noted, the new Childers/Dodson target range is above difficulty 260; but we did do a couple from the 1st five on the way up (notably 12,241 C260 Childers/Wackerbarth/Dodson). I'm on the last range of width 20M (out of 30M-250M) on 3,547-, after which I'll have four large matrices to deal with --- pending full production and data exchange to Greg's new machine, sieving is still way out-running our matrix resources. We clearly ought to be sieving harder/larger numbers so as to give the matrix queue a chance to clear. -Bruce |
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#5 |
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(loop (#_fork))
Feb 2006
Cambridge, England
2×132×19 Posts |
I wouldn't be very optimistic that sieving harder numbers will give the matrix queue a chance to clear, unless you deliberately use sub-optimal large prime bounds: I get the strong impression that we're at a stage where harder numbers will have much harder matrices, and msieve is already taking a couple of months on four cores to handle a 20M matrix.
Or possibly block-Weidemann will be available by the time the sieving for a 900-bit number has finished, in which case all bets are off. |
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#6 | |
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"Ben"
Feb 2007
351610 Posts |
Quote:
Comments/advice? |
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#7 | |
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Jun 2005
lehigh.edu
100000000002 Posts |
Quote:
thanks for the reply on the msieve thread). So I want the next number to take more than a week to sieve. The number 10,257+ at difficulty 257 was within a few hours of completely finishing sieving in under seven days (although other users arrived, which added two days to the walltime). The matrix for 10,257- is smaller/easier than 3,536+ despite being a harder number (due to oversieving). I do seem to have disk space for four large matrices (barely) once 3,547- finishes sieving later today; so 536+ will make space for 2,949+ and 257- will make space for the one after that (both candidates having recently been c258's). Your reply gives a long-term analysis for what we hope is a short-term problem (pending my being able to ship a matrix or two off to Greg's new machine, so we can alternate matrices and double the available time for running harder numbers). We're mostly waiting for Greg's C260 to finish to see where things stand. -Bruce |
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#8 |
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"Ben"
Feb 2007
22×3×293 Posts |
I've done some trial sieving on 2,799+ with various parameterizations
Rational side sieving of this polynomial Code:
n: 17046484339439502390787014663843382603841990311536588019427381788315112645544913528357093997566704677217496355462170676223202258500459624221675999642483043420478565738287873667689291 skew: 1 c6: 2 c0: 1 Y1: -1 Y0: 10889035741470030830827987437816582766592 rlim: 85000000 alim: 75000000 lpbr: 30 lpba: 30 mfbr: 60 mfba: 60 rlambda: 2.6 alambda: 2.6 Algebraic side tests yielded less relations, and took longer, so rational side seems to be the way to go. 31 bit tests seemed to show that as many or more special-q would be needed, with the accompanying headaches of shuffling around twice as much data, so 30 bits seems to be the way to go. I can probably sustain 3 to 5 million special-q per day, depending on cluster usage by others, so this would take anywhere from 20 to 40 days, depending on actual yield and resource availability. *deep-breath* I'll go ahead and reserve it. Other stuff in my queue will push the start out to next week sometime. Suggestions/tweaks to parameters welcome. - ben. |
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#9 | |
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Nov 2003
22·5·373 Posts |
Quote:
factor of 2^47 (i.e. it becomes 752 bits), but we would have to work with a reciprocal octic polynomial....... Which is quite sub-optimal. But it would be an interesting experiment..... |
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#10 | |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
47×229 Posts |
Quote:
I doubt, however, that the duplication rate will be 6%, the value of (85-80)/85, but is rather more likely to be 20-25%. At least, that's been my experience with numerous lattice sievers in the past. I would assume 90-100M raw relations will be required. You may be pleasantly surprised in the end but setting expectations to realistic values before a large computation is almost always a good thing, IMO. Paul |
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#11 | |
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"Ben"
Feb 2007
1101101111002 Posts |
Quote:
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