Bases 6-32 reservations/statuses/primes

[KEP]

@ Gary: Well I has a feeling that it will be faster, but you are more experienced than I am, and with my quad (hopefully getting it tomorrow), I may consider to go to at least n=5,000. Actually the quad may be far from attacking and reenforcing the base 3 attack. At the moment I'm seriously considering to use 1 of the cores on sieveing the Base 19, actually preperation is already in progress, and currently I've begun using srsieve sieving from 10,001 to 250,000. I seriously consider running that range and reduce the amount of k's drasticly over the coming months. I know that I'm reserving loads of work at the moment, but at least this gives me a chance to contribute to something rather usefull. So hey please also sign me on this range: n>10000 > n =250000 for sierpinski base 19, all k's!

Thanks, and after sometime I think 2-3 month from now, this quad may be shipped to base 3 conjecture and to work with that one only, so we can consider this enrolement as praxis for the future and bigger battle it will enlist in

KEP!

[gd_barnes]

Originally Posted by KEP

@ Gary: Well I has a feeling that it will be faster, but you are more experienced than I am, and with my quad (hopefully getting it tomorrow), I may consider to go to at least n=5,000. Actually the quad may be far from attacking and reenforcing the base 3 attack. At the moment I'm seriously considering to use 1 of the cores on sieveing the Base 19, actually preperation is already in progress, and currently I've begun using srsieve sieving from 10,001 to 250,000. I seriously consider running that range and reduce the amount of k's drasticly over the coming months. I know that I'm reserving loads of work at the moment, but at least this gives me a chance to contribute to something rather usefull. So hey please also sign me on this range: n>10000 > n =250000 for sierpinski base 19, all k's!

Thanks, and after sometime I think 2-3 month from now, this quad may be shipped to base 3 conjecture and to work with that one only, so we can consider this enrolement as praxis for the future and bigger battle it will enlist in

KEP!

I forgot to respond to your base 19 reservation: How about I just reserve n=10K-100K for you? n=10K-250K is likely to be 10-25 CPU YEARS of work!! 10K-100K is probably 3-4 CPU years but not unreasonable if you throw a quad at it. I'm suggesting this because I can almost guarantee that you'll probably get bored with it at some point and will want to put your machine(s) on something different. (Yes, I'm speaking from experience here.)

The main reason I'm suggesting this is because base 19 tests FAR slower than base 3 because you're testing bigger numbers! (duh, lol)

OK...I must quit responding for today or I'll never get the pages completed or the work on my machines redistributed.


Gary

[gd_barnes]

Originally Posted by Siemelink

Haliho,

Here is an update on my efforts. For Riesel base 19 I have reached n=25,000. There are 1605 k's remaining (attached). I've removed the k's as Gary suggested. I am continuing for a few more months, I am aiming for n=30,000
With my Riesel 25 effort I've almost reached n=10,000. When I have done so I'll post the remaining k's. At the moment there are 474 k.

Enjoy, Willem.

Willem,

I have removed 66 squared k's from the web pages that have algebraic factors for Riesel base 19. That leaves 1736 k's remaining at n=17K, down from 1802 k's previously. Here is a list of the k's that were removed:

144, 324, 1764, 2304, 5184, 6084, 10404, 11664, 17424, 19044, 26244, 28224, 36864, 39204, 49284, 63504, 66564, 79524, 82944, 97344, 101124, 121104, 138384, 142884, 161604, 166464, 186624, 191844, 213444, 219024, 242064, 248004, 272484, 278784, 304704, 311364, 338724, 345744, 374544, 381924, 412164, 419904, 451584, 459684, 492804, 501264, 535824, 544644, 580644, 589824, 627264, 675684, 685584, 725904, 736164, 777924, 788544, 842724, 887364, 898704, 944784, 956484, 1004004, 1016064, 1065024, 1077444

In order to remove additional k's for n=17K-25K here to reflect 1605 k's remaining, I'll need to get the primes for that range from you.

Edit: I just now compared the list that you sent of k's remaining to what I showed remaining at n=17K. There are 134 k's that are on my list at n=17K that are not on your list at n=25K. With that being the case, there should be 1602 k's remaining at n=25K. Somewhere something is off by 3 k's. The primes will help find where. I suspect there is are some k's that are multiples of the base (that I previously listed) or that are squared k's that did not get removed from your testing but that's only a guess.


Thanks,
Gary

[mdettweiler]

Note: moved KEP's latest post about Sierp. base 3 to the base 3 thread

[mdettweiler]

LLRnet IB6 has completed k=10107, k=13215, and k=14505 for the range n=60K-100K. No primes. lresults are attached.

Edit: Oh, forgot to mention, LLRnet is releasing these k's.

[Siemelink]

Originally Posted by gd_barnes

Willem,

In order to remove additional k's for n=17K-25K here to reflect 1605 k's remaining, I'll need to get the primes for that range from you.

Edit: I just now compared the list that you sent of k's remaining to what I showed remaining at n=17K. There are 134 k's that are on my list at n=17K that are not on your list at n=25K. With that being the case, there should be 1602 k's remaining at n=25K. Somewhere something is off by 3 k's. The primes will help find where. I suspect there is are some k's that are multiples of the base (that I previously listed) or that are squared k's that did not get removed from your testing but that's only a guess.

Thanks,
Gary

Gary, thank you for checking.

I've sent the primes to you. I have it all sitting in an excel so it it easy to cough up. I didn't use the k's you posted, I was cutting and pasting myself. These are the k's that are divisible by 19 that I still included in the search:
53694
124754
132126
192014
234194
255474
265164
419444
486324
595004
640224
641136
650864
666824
928454
946124
1020186

Is that the same as what you came up with?

Willem.

[gd_barnes]

Originally Posted by Siemelink

Gary, thank you for checking.

I've sent the primes to you. I have it all sitting in an excel so it it easy to cough up. I didn't use the k's you posted, I was cutting and pasting myself. These are the k's that are divisible by 19 that I still included in the search:
53694
124754
132126
192014
234194
255474
265164
419444
486324
595004
640224
641136
650864
666824
928454
946124
1020186

Is that the same as what you came up with?

Willem.

After a concerted balancing effort after removing all appropriate multiples of the base and perfect squares where k==(4 mod 10), I have determined that there are actually 1603 k's remaining at n=25K, which is 2 different than what you have. Here are the differences:

1. k=132126 is divisible by 19^2 and so reduces to k=366. Since k=366 is remaining, you can remove k=132126 from your search. (You had already removed k=132126/19=6954 from your search.)

2. k=641136 is divisible by 19^2 and so reduces to k=1776. Since k=1776 is remaining, you can remove k=641136 from your search. (You had already removed k=641136/19=33744 from your search.)

3. k=1020186 is divisible by 19^2 and so reduces to k=2826. But k=2826 has a prime only at n=1. So taking it further...k=1020186 is divisible by 19 and so can also reduce to k=53694. Since k=53694 is remaining, you can remove k=1020186 from your search.

OK, so that's 3 removed from your search but:

You are missing the very last k of k=1119866. You'll need to find out where you stopped testing it and retest it from that point (or perhaps you just missed a line when you cut-and-pasted your k's remaining that you sent to me).

That makes a difference of 2 k's between you and me. You reported 1605 remaining. Subtracting off the above difference of 2 leaves 1603 k's remaining at n=25K for Riesel base 19. That is what will be reflected on the web pages.


Gary

[Siemelink]

Originally Posted by gd_barnes

1. k=132126 is divisible by 19^2 and so reduces to k=366.
2. k=641136 is divisible by 19^2 and so reduces to k=1776.
3. k=1020186 is divisible by 19^2 and so reduces to k=2826.

OK, so that's 3 removed from your search but:
You are missing the very last k of k=1119866.
Gary

Ah, those three suffered from a systematic error from my part. Good catch. I'll have a look tomorrow when I am on the right machine.

The last k = 1119866 is actually the conjectured riesel number. There is no real need to test that one. It just took me a while to figure out why the sieve would always remove it from sieving.

Willem.

[gd_barnes]

Originally Posted by Siemelink

Ah, those three suffered from a systematic error from my part. Good catch. I'll have a look tomorrow when I am on the right machine.

The last k = 1119866 is actually the conjectured riesel number. There is no real need to test that one. It just took me a while to figure out why the sieve would always remove it from sieving.

Willem.

Well, DUH on k=1119866. I must have been smoking something there! I'll remove it from the web page. So there are officially 1602 k's remaining at n=25K on Riesel base 19.


Gary

[gd_barnes]

Sierp base 16 k=2908, 6663, and 10183 are now complete to n=184K. No primes yet. Continuing on to n=200K.


Gary

[rogue]

BTW, all base 28 k (Sierpinski) are tested to n = 100,000. I made a mistake and did not test the base 28 Riesels. You can unreserve them

I will reserve the Sierpinski and Riesel base 27 k.

Base 30 is nearing completion to n = 100,000, but is on a slower PC, so it will take a little while longer.