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#1 |
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Nov 2003
22×5×373 Posts |
Would someone with access to a CA package please find
the coefficients of the reciprocal sextic for 2,1694M? The 2^1694M/2^242M is 2^726 - 2^666 + 2^605 - 2^484 + 2^424 - 2^363 + 2^303 - 2^242 + 2^121 - 2^61 + 1 This should be expressible as a sextic polynomial in (2x + 1/x) with x = 2^61. Doing it by hand is a mess. |
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#2 |
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(loop (#_fork))
Feb 2006
Cambridge, England
2×132×19 Posts |
Don't you mean x=2^60 here?
Code:
% gp a = factor(2^14*x^28+1)[3,1] u = 2*x + 1/x (x^6 * (u^6-2*u^5-10*u^4+20*u^3+16*u^2-32*u+8)) - a u^6-2*u^5-10*u^4+20*u^3+16*u^2-32*u+8 with u = 2x+1/x, x=2^60 Tom |
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#3 |
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"Robert Gerbicz"
Oct 2005
Hungary
2·743 Posts |
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#4 | |
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(loop (#_fork))
Feb 2006
Cambridge, England
2×132×19 Posts |
Quote:
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#5 | |
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Nov 2003
22·5·373 Posts |
Quote:
I am not allowed to download any software over the net owing to security considerations. |
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#6 | |
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Jun 2003
The Texas Hill Country
32·112 Posts |
Quote:
AFAICT, this is a website address that allows you to run a "simple" magma calculation on THEIR server and returns the result to you. Nothing is "downloaded". It is a simple submit/response system. |
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#7 |
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Nov 2003
22·5·373 Posts |
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#8 | |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
47·229 Posts |
Quote:
![]() Paul Last fiddled with by xilman on 2007-12-21 at 16:10 Reason: Boy, am I going to get into trouble for this one! |
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#9 | |
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Nov 2003
22·5·373 Posts |
Quote:
Writing such code would not give me a sense of accomplishment. I would learn nothing in the process. It is an easy, but *tedious* exercize in junior high school algebra. I just don't have the time to write such a program. My time is better spent on developing new ideas. I don't ask others to solve any of my problems unless I already know how to do it myself. |
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