help?

Orgasmic Troll · 2003-10-06, 23:24

How would I go about proving or disproving the following:

7/8(256a²+14b²+c²) < 64ab + 4bc + 16ac

has no solutions for integers a, b, c > 0

Thanks!

Orgasmic Troll · 2003-10-07, 03:58

gar. edited one problem and missed the other ..

7/8(256a²+16b²+c²) < 64ab + 4bc + 16ac

this is the correct problem

Orgasmic Troll · 2003-10-07, 04:06

n/m

Found counter examples :)

2003-10-06, 23:24	#1
Orgasmic Troll Cranksta Rap Ayatollah Jul 2003 641 Posts	help? How would I go about proving or disproving the following: 7/8(256a²+14b²+c²) < 64ab + 4bc + 16ac has no solutions for integers a, b, c > 0 Thanks! Last fiddled with by Orgasmic Troll on 2003-10-06 at 23:25

2003-10-07, 04:06	#3
Orgasmic Troll Cranksta Rap Ayatollah Jul 2003 281₁₆ Posts	n/m Found counter examples :) Last fiddled with by Orgasmic Troll on 2003-10-07 at 04:07

2003-10-07, 03:58	#2
Orgasmic Troll Cranksta Rap Ayatollah Jul 2003 641 Posts	gar. edited one problem and missed the other .. 7/8(256a²+16b²+c²) < 64ab + 4bc + 16ac this is the correct problem