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#1 |
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Sep 2002
22·3·5 Posts |
I'm having trouble with this problem:
Factor: (4)(a^2)(c^2) - (a^2 - b^2 + c^2)^2 Thanks |
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#2 |
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Nov 2002
2×37 Posts |
==>
(4)(a^2)(c^2) - (a^2 - b^2 + c^2)^2 = - (a + b + c)·(a + b - c)·(a - b - c)·(a - b + c) hope i could help you andi314 |
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#3 |
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Sep 2002
22·3·5 Posts |
I have checked and the answer is correct, and I have accidentally found a way to find the factors, but it was through major guessing. Could anyone show how to factor this out fully?
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#4 | |
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"Richard B. Woods"
Aug 2002
Wisconsin USA
22×3×641 Posts |
There are online factorers. The one I frequently use is "Factoris" at http://wims.unice.fr/wims/wims.cgi It can factor an integer, a rational number, a polynomial or a rational function.
When given: 4(a^2)*(c^2)-(a^2-b^2+c^2)^2 Factoris returned: Quote:
Factoris doesn't use "*" for multiplication in its output even though it wants you to use it in input. :) Of course, Factoris doesn't tell you how to factor an expression. But one might get clues from its answers. |
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#5 | |
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Jun 2003
116748 Posts |
Quote:
(4)(a^2)(c^2) - (a^2 - b^2 + c^2)^2 ==> X^2 - Y^2, where X = 2ac and Y = (a^2 - b^2 + c^2) ==> (X+Y)(X-Y) ==> (2ac + a^2 - b^2 + c^2)(2ac - a^2 + b^2 - c^2) ==> [(a+c)^2 - b^2] [b^2 - (a-c)^2] ==>[(a+c+b)(a+c-b)] [(b+a-c)(b-a+c)] |
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