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Old 2019-10-09, 19:46   #1
Jun 2019

32 Posts
Default Condition on composite numbers easily factored (Challenger)

q prime numbre

p prime numbre
and q>p
lets c = qp

e= 2^p mod q

if we know e we can factore (c)

ok letz try with c and e

Last fiddled with by baih on 2019-10-09 at 19:51
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