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Old 2003-09-15, 22:18   #4
GP2
 
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Sep 2003

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To summarize, the algorithm I use is:

If an exponent has had 1 LL test done:
- We can't draw any conclusions.

If an exponent has had (N > 1) LL tests done, with a match:
- We know exactly how many of the N tests are good and how many are bad

If an exponent has had (N > 1) LL tests done, with no match:
- We know that at least N-1 of the tests are bad.
- Assume N-1 bad and 1 good, because that's much more likely than all N bad.
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