View Single Post
Old 2017-07-24, 12:24   #1
Sep 2011

3·19 Posts
Default Inverse of Smoothness Probability

The probability that a random number below X is B-smooth is given by u-u, where u=ln(X)/ln(B). However, I would like the do the inverse, that is, given the smoothness probability and B, how do I solve for X?

I have a solution via Newton method. Is there a closed form?
paul0 is offline   Reply With Quote