mersenneforum.org - View Single Post - k*b^n+/-c where b is an integer greater than 2 and c is an integer from 1 to b-1

axn · 2016-04-23, 11:15

Are you saying that if one studies jjsieve source, one will find a new method to test numbers of the form k*b^n+/-c?

2016-04-23, 11:15	#3
axn Jun 2003 3·5·17·19 Posts	Are you saying that if one studies jjsieve source, one will find a new method to test numbers of the form k*b^n+/-c?