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Old 2019-04-13, 16:55   #14
VBCurtis
 
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"Curtis"
Feb 2005
Riverside, CA

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Quote:
Originally Posted by MathDoggy View Post
What if I do a proof like this?
If the set of twin prime numbers is finite then we can make a list, let S be the list of twin prime numbers,
S=P1,P2,P3,P4,PN
Now let us construct a number Q such that Q=P1×P2×P3×P4×PN+1
If Q is a twin prime then there exists a larger twin prime then on S
If Q is composite then non of the twin primes of S will divide Q.
Both of this conclusions yield to a contradiction, therefore there are infinitely many twin prime numbers
Where is the contradiction if Q is composite? If Q is composite, then Q is divisible by primes that aren't twin primes. That's hardly contradictory.
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