Thread
:
Proving, for A > 1, (A+1)^n mod A = 0
View Single Post
2017-12-20, 23:51
#
3
henryzz
Just call me Henry
"David"
Sep 2007
Cambridge (GMT)
2
^{6}
×89 Posts
As it stands I believe it to be false. For n >= 0, it is fairly easy to show that (A+1)^n = 1 mod A.
henryzz
View Public Profile
Find More Posts by henryzz