Thread: Simple Diophantine equation View Single Post
 2009-04-10, 01:20 #1 Batalov     "Serge" Mar 2008 Phi(4,2^7658614+1)/2 242F16 Posts Simple Diophantine equation $a^3 = b^5 + 100$ Is there more than one solution? ________ P.S. Argh, I only started playing with modular restrictions, and you've already looked up to 10^35. If so, then of course I am convinced, too. Sorry, then it was ...too simple. Last fiddled with by Batalov on 2009-04-10 at 02:12