Thread: Odds of prime discussion View Single Post
 2013-10-27, 12:53 #25 TheCount     Sep 2013 Perth, Au. 2·72 Posts I was using srsieve_0.6.17 which has been the latest version since May 31, 2010 as far as I can tell. Yes all these bases have one or two k being a perfect cube or square. Does srsieve need some special flag to take account of perfect cubes or squares? Or do I need to do another step before/after using srsieve? For R463: >srsieve -n 100001 -N 110000 -P 1e6 "216*463^n-1", I get 269 terms remaining >srsieve -n 100001 -N 110000 -P 1e6 "356*463^n-1", I get 252 terms remaining For R696: >srsieve -n 100001 -N 110000 -P 1e6 "152*696^n-1", I get 705 terms remaining >srsieve -n 100001 -N 110000 -P 1e6 "225*696^n-1", I get 1014 terms remaining For R774: >srsieve -n 100001 -N 110000 -P 1e6 "25*774^n-1", I get 671 terms remaining >srsieve -n 100001 -N 110000 -P 1e6 "30*774^n-1", I get 447 terms remaining For R588: >srsieve -n 100001 -N 110000 -P 1e6 "3*588^n-1", I get 795 terms remaining >srsieve -n 100001 -N 110000 -P 1e6 "16*588^n-1", I get 664 terms remaining For R828: >srsieve -n 100001 -N 110000 -P 1e6 "64*828^n-1", I get 404 terms remaining >srsieve -n 100001 -N 110000 -P 1e6 "68*828^n-1", I get 676 terms remaining For S140: >srsieve -n 100001 -N 110000 -P 1e6 "8*140^n+1", I get 328 terms remaining >srsieve -n 100001 -N 110000 -P 1e6 "16*140^n+1", I get 642 terms remaining For S533: >srsieve -n 100001 -N 110000 -P 1e6 "38*533^n+1", I get 747 terms remaining >srsieve -n 100001 -N 110000 -P 1e6 "64*533^n+1", I get 691 terms remaining The values I get are always higher, so it's consistent that more factors needing to be eliminated. Keeping on top of all these conjectures is a really big task and you and others obviously put in a massive effort. I am sure everyone appreciates it.