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Old 2013-05-12, 19:35   #5
Batalov
 
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Mar 2008
Phi(4,2^7658614+1)/2

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Many solutions. Here's just a few:
v=[3,14,15];sum(k=1,#v,1/(73*v[k])+1/(137*v[k]))
v=[3,10,42,70];sum(k=1,#v,1/(73*v[k])+1/(137*v[k]))
v=[5,6,14,30];sum(k=1,#v,1/(73*v[k])+1/(137*v[k]))
v=[7,10,14,15,21,35,70];sum(k=1,#v,1/(73*v[k])+1/(137*v[k]))

Last fiddled with by Batalov on 2013-05-12 at 19:50 Reason: (add a long one)
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