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Old 2019-01-05, 18:31   #6
science_man_88
 
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Jul 2009
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Quote:
Originally Posted by enzocreti View Post
what instead about the equation:


a(2*a^2+2*b^2+c^2+d^2)=(2*a^3+2*b^3+c^3+d^3)?


Again a=1,b=1,c=1,d=1 is a solution
a=5, b=4, c=6, d=1 is another solution


are there solutions with d>1?
if a is even c and d need be same parity.
if a=b then ac^2+ad^2=c^3+d^3

etc.
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