Thread: Chebyshev's Estimates View Single Post
 2009-01-22, 17:21 #3 brownkenny     Jan 2009 2×3 Posts Thanks for the suggestion, Dr. Silverman. When I made the substitution I wound up with a log(log(n)) term in the denominator that I'm not sure how to get rid of. I tried estimating some more, but I still can't figure out where the factor of 8 in the term $ \frac{8 \log \log n}{\log n}$ comes from. Thanks again, Dr. Silverman.