Thread: Riesel primes
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Old 2009-07-18, 05:54   #3
Primeinator's Avatar
Feb 2005
Somewhere near M50..sshh!

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Originally Posted by Mini-Geek View Post
I'm pretty sure it's only that n is such that 2^n>k (otherwise every number would be a Riesel number, and every prime a Riesel prime).
How would 2^n < k in of itself make a number riesel? I thought that any number of the form k*2^n -1 is a riesel number.
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