Double Check P1
I was just assigned a Double Check in which P1 factoring had not been done. This is a new one on me. I guess this means if an exponent gets assigned to a machine that does not have enough memory to do the normal P1 factoring then the machine assigned the double check does the P1. Please correct me if I'm wrong.
I'm curious. What if I find a factor? I guess that means the exponent will go to the cleared list, and the first LL test will remain in the unverified list forever?
Last fiddled with by PhilF on 20050702 at 02:57
