Quote:
Originally Posted by axn
"Size of N" is the digit length of N, which is basically O(log(N))

Okay. But it still doesn't meet the criterion 99%.
log(6¹⁰⁰)/log(7×6¹⁰⁰+11) = 98.92...%
Indeed for any integer N I can't see how you ever get 99%. The only way would be something like e×e⁹⁹+0 = 99%. So k=e, b=e, n=99, c=0. And other multiples of those values.