Thread: Combinatorics
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Old 2006-05-12, 19:25   #6
tom11784
 
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Aug 2003
Upstate NY, USA

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If you number the subsets by ranking from least to greatest for first term, then second term, then third term, then fourth
i.e. A1={1,2,3,4} A2={1,2,4,3} A3={1,3,2,4} A4={1,3,4,2} ...

and f({a,b,c,d})={a,b,c}

then B1={1,2,3} B2={1,2,4} B3={1,3,2} B4={1,3,4} ...

which I believe meets your requirements, but I may be reading something incorrectly
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