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Old 2018-01-15, 20:02   #11
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Jul 2009

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Originally Posted by Nick View Post
Not only that, this solves ( or at least heuristics) the first 3 all wihout direct invocation of fermat's little theorem.

1) noted above.
2)see formula from 1, M_m= 2^{m-n}M_n+M_{m-n} q divides the first term, and so q must divide into the second term in order to divide the LHS.
3) following from 2, if q divides other mersennes other than multiples, it follows there is no minimal p, this leads to the absurdity that 1/ q is integer.

Last fiddled with by science_man_88 on 2018-01-15 at 20:03
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