Thread: angle bisection
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Old 2017-11-09, 22:16   #5
Dr Sardonicus
 
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tan(\frac{\alpha}{2})=\frac{sin(\frac{\alpha}{2})}{cos(\frac{\alpha}{2})}=<br />
\frac{2*sin(\frac{\alpha}{2})*cos(\frac{\alpha}{2})}{2*cos^{2}(\frac{\alpha}{2})}=<br />
\frac{sin(\alpha)}{(1+cos(\alpha))}=\frac{sin(\alpha)-sin(\alpha)*cos(\alpha)}{sin^{2}(\alpha)}<br />
=cosec(\alpha)-cot(\alpha)
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