1527888802614951*2^120 + 1

1527888802614951 has 16 digits ,

if we calculate and try 10^5 per second ,

it will cost 10^15/(365*24*60*60)/10^5=317.1years for us to find this factor ,

Peter Strasser found this factor of F118,

and F118 approximate has 10^35digits , so it is impossible to find this factor by ECM .

who can tell me how to find this factor of F118

F118=2^(2^118)+1

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