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:
"New" same approach that isn't factorization
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2020-09-10, 12:20
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15
Alberico Lepore
May 2017
ITALY
111100101
_{2}
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Bruteforce could be attempted for a multiple of 9 :
9*F
N=161
,
2*(N*9*F)+2*a^2+((b-a)/2)^2=((3*a+b)/2)^2
,
a*b=(N*9*F)
,
2*(N*9*F)+2*1^2+((a+b)/2+1)^2-((3*a+b)/2)^2=0
,
F=15
->
a=105
GCD(105,161)=7
but I think this is very RANDOM
Alberico Lepore
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