Quote:
Originally Posted by VBCurtis
I expect 100120 days to reach 2500, and less than twice that to reach 10,000.

I hope you're planning on adding a whole lot of resources for n=250010K. :)
n=250010K is 3 times the nrange of n=12500.
A test at half the nrange for n=250010K (n=6250) would take 25 times as long as a test at half the nrange for n=12500 (n=1250) since the nvalue is 5 times as big.
Extrapolating: 3 times the nrange x 25 times the testing time = 75 times as long for n=250010K vs. n=12500.
Allowing for a reduction in k's remaining on the higher range perhaps cut that by onehalf to twothirds so maybe 2550 times as long.
I realize that this is overly simplified but I've found it to be a reasonable predictor of estimating a higher nrange after completing a lower nrange.
Perhaps I'm off base since you're going from 20 million k's at the beginning to 100,000 k's remaining at n=2500. But most of those 20 million k's are very quickly eliminated so I feel it's still a valid analysis.
My rough guess: If it takes you 4 months to complete to n=2500, with the same amount of resources it will take you (4x30* months= 120 months or) 10 years to complete to n=10K plus or minus a few years.
Feel free to stop at n=2500 if you'd like. :)
*I chose 30 since it's on the lower end of the 2550 times as long estimate.