Quote:
Originally Posted by Ale
now 8 is:
3 x 3 x 2 x 4 x 3 x 2 x 3 x 4 x 5 x 3 x 2 x 4 x 3 x 4 x 5 x 6 x 3 x 4 x 5 x 3 x 4 x 5 x 6 x 3 x 5 x 6 x 7 x3 x 2 x 4 x 5 x 6 x 3 x 4 x 5 x 6 x 3 x ? 6 x 7 x 8 = n  1 = prime number
or
x ? 5 x 6 x 7 x 8 = n  1 = prime number
I can not test the true mechanism , but i think ( you see 4 x 5 x 6 , 3 times , and the number moltiplication 3 always after a series of numbers ) , i think that ,in this mechanism there is peralps hide one algorithm particular for to find a prime numbers.

I assume the '?' in there is a stray character  deleting it and replacing the 'x' with '*', PARI (which is a freely downloadable for you as it was for me, hint, hint) shows this number is composite:
? factor(3*3*2*4*3*2*3*4*5*3*2*4*3*4*5*6*3*4*5*3*4*5*6*3*5*6*7*3*2*4*5*6*3*4*5*6*3*6*7*81)
%2 =
[71 1]
[11214507891272978028169 1]
And you still have not given an actual *algorithm* for how you generate these smallnumber product sequences. Please do so  it should only require very rudimentary English. Do it in Italian and then post it here, if you prefer  I'm sure one of our Italianspeaking regular readers could translate it.
If by '?' you mean 'I am not sure here', then in fact you have no algorithm, just a vague supposition  in that case, download PARI, learn its basic operations (*,+,, isprime and factor are the main operators and functions you need), and see if you can work out an actual *algorithm* which generates more than 3 or 4 primes in succession.