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Old 2019-04-15, 13:55   #23
retina
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"The unspeakable one"
Jun 2006
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Quote:
Originally Posted by MathDoggy View Post
It is impossible because we constructed an arbitrary number Q which is the product of the finite list of the twin primes and adding 1 to the product
2×3×5×7×11×13+1 = 59×509

And if 2 isn't a twin prime then 3×5+1 = 2×2×2×2

Either way there are always possible divisors that aren't in the original set of primes you multiplied together.

Last fiddled with by retina on 2019-04-15 at 13:55
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