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Old 2018-03-15, 12:12   #6
JeppeSN
 
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"Jeppe"
Jan 2016
Denmark

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Quote:
Originally Posted by axn View Post
what is the form of factors for these numbers? It will be k*2^14+1, but will k itself has other restrictions (like k is a multiple of 2 or 4 or something? other modular restrictions?)
I would say the multiplier must be even, so it becomes (under a new convention where k is odd) \(k\cdot 2^n + 1\) where \(n \ge 15\). See also New GFN factors (Wilfrid Keller).

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