Quote:
Originally Posted by kalikidoom
...(2^(2^(2^n1)1)1)...
I mean... isn't that at least a proof that there's an infinate amout of them?
Try it with how meny primes you like... and with how meny 2^....1 you like... it always works

1) n must be prime for 2^n1 to be prime
2) by that same logic m=2^n1 must be prime for 2^m1= 2^(2^n1)1 to have a chance at being prime.
3) as LaurV pointed out not all n that are prime will allow 2^n1 to be prime.