View Single Post
Old 2015-09-09, 03:36   #11
R.D. Silverman
R.D. Silverman's Avatar
Nov 2003

22×5×373 Posts

Originally Posted by R.D. Silverman View Post
One way of doing it for x^2 + 1 is to factor it as (x+i) (x-i), then search for x such that the norms
(over Q) of the factors are both prime.
I'm an idiot. This won't work. The norm of each factor is the product of all its conjugates......
Now ask: what are the conjugates of each factor???

Still, it seems that something similar might work.... I will consider it.
R.D. Silverman is offline   Reply With Quote