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Old 2005-09-23, 08:59   #50
Thomas11's Avatar
Feb 2003

1,901 Posts

The values of k I'm working on are all sieved to pmax=12T yet, with nmax=10M.
If you want to do n=0...2M, then pmax=4T should be quite sufficient.
One could also think of using SBFactor to do some P-1 factoring on candidates with n>1M.
I did some trials but found the sieving still more efficient. Maybe SBFactor will get another chance at even larger values of n.

-- Thomas
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