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Old 2013-10-27, 12:53   #25
TheCount
 
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Sep 2013
Perth, Au.

6216 Posts
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I was using srsieve_0.6.17 which has been the latest version since May 31, 2010 as far as I can tell.
Yes all these bases have one or two k being a perfect cube or square.
Does srsieve need some special flag to take account of perfect cubes or squares?
Or do I need to do another step before/after using srsieve?
For R463:
>srsieve -n 100001 -N 110000 -P 1e6 "216*463^n-1", I get 269 terms remaining
>srsieve -n 100001 -N 110000 -P 1e6 "356*463^n-1", I get 252 terms remaining
For R696:
>srsieve -n 100001 -N 110000 -P 1e6 "152*696^n-1", I get 705 terms remaining
>srsieve -n 100001 -N 110000 -P 1e6 "225*696^n-1", I get 1014 terms remaining
For R774:
>srsieve -n 100001 -N 110000 -P 1e6 "25*774^n-1", I get 671 terms remaining
>srsieve -n 100001 -N 110000 -P 1e6 "30*774^n-1", I get 447 terms remaining
For R588:
>srsieve -n 100001 -N 110000 -P 1e6 "3*588^n-1", I get 795 terms remaining
>srsieve -n 100001 -N 110000 -P 1e6 "16*588^n-1", I get 664 terms remaining
For R828:
>srsieve -n 100001 -N 110000 -P 1e6 "64*828^n-1", I get 404 terms remaining
>srsieve -n 100001 -N 110000 -P 1e6 "68*828^n-1", I get 676 terms remaining
For S140:
>srsieve -n 100001 -N 110000 -P 1e6 "8*140^n+1", I get 328 terms remaining
>srsieve -n 100001 -N 110000 -P 1e6 "16*140^n+1", I get 642 terms remaining
For S533:
>srsieve -n 100001 -N 110000 -P 1e6 "38*533^n+1", I get 747 terms remaining
>srsieve -n 100001 -N 110000 -P 1e6 "64*533^n+1", I get 691 terms remaining
The values I get are always higher, so it's consistent that more factors needing to be eliminated.

Keeping on top of all these conjectures is a really big task and you and others obviously put in a massive effort.
I am sure everyone appreciates it.
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