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Old 2006-03-23, 21:50   #6
R.D. Silverman
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Nov 2003

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Originally Posted by NeoGen
Thanks guys. :)

For a while I was confused about the "mod" operator, as english is not my native language, and many times I had seen referenced "mod" as the remainder of a division, and it didn't make sense here.
But I dug out a bit more and found out that in number theory is a little different than that. :)
Generally, in the context in which it arises within this forum, 'mod' is
NOT an operator. It is an equivalence class.
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